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Alina [70]
2 years ago
13

HELP ASAP PLEASE.

Mathematics
1 answer:
Schach [20]2 years ago
8 0

Answer:

5(6)81 because the are

Step-by-step explanation:

6•82

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What is the radius of a sphere with a surface area of 100TCm ?
tensa zangetsu [6.8K]

The radius is 5cm

Step-by-step explanation:

The surface area of a sphere is given by:

SA = 4\pi r^2

Here

Given

SA = 100π cm^2

Putting the values in the formula

100\pi = 4\pi r^2\\r^2 = \frac{100\pi}{4\pi}\\r^2 = 25

Taking square root on both sides

\sqrt{r^2} = \sqrt{25}\\r = 5 cm

The radius is 5cm

Keywords: Surface area, Radius

Learn more about surface area of sphere at:

  • brainly.com/question/1388658
  • brainly.com/question/1386181

#LearnwithBrainly

7 0
3 years ago
Talya works six hours per day on Fridays and Saturdays each week she earns $8.20 per hour what is her gross pay in a week
Scilla [17]

6 \times 2 = 12
12×8.20=98.40
5 0
3 years ago
What is the distance between the points (5.-18) and (8,
romanna [79]

Answer:

\sqrt{10}

Step-by-step explanation:

The horizontal distance from points (5,-18) and (8,-17) is 3 because it is 3 units from 5 to 8.  The vertical distance is 1 since it is one unit from -18 to -17.  Now we can use the equation a^{2}+b^{2}=c^{2} where a=3 and b=1 and c is the distance that you are looking for:

a^{2} +b^{2} =c^{2}\\3^{2} +1^{2} =c^{2}\\9+1=c^{2}\\10=c^{2}\\\sqrt{10}=c

8 0
2 years ago
Read 2 more answers
In the figure, TP and TS are opposite rays. TQ bisects < RTP.
Ket [755]

Answer:

search-icon-image

Class 9

>>Maths

>>Quadrilaterals

>>Quadrilaterals and Their Various Types

>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2

Question

Bookmark

In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28

0

and ∠QRT=65

0

, then find the values of x and y.

463685

expand

Medium

Solution

verified

Verified by Toppr

Given, PQ⊥PS,PQ∥SR,∠SQR=28

∘

,∠QRT=65

∘

According to the question,

x+∠SQR=∠QRT (Alternate angles as QR is transversal.)

⇒x+28

∘

=65

∘

⇒x=37

∘

Also ∠QSR=x

⇒∠QSR=37

∘

Also ∠QRS+∠QRT=180

∘

(Linear pair)

⇒∠QRS+65

∘

=180

∘

⇒∠QRS=115

∘

Now, ∠P+∠Q+∠R+∠S=360

∘

(Sum of the angles in a quadrilateral.)

⇒90

∘

+65

∘

+115

∘

+∠S=360

∘

⇒270

∘

+y+∠QSR=360

∘

⇒270

∘

+y+37

∘

=360

∘

⇒307

∘

+y=360

∘

⇒y=53

∘

Step-by-step explanation:

please mark me as brainlist please

6 0
2 years ago
Plz plz help i have till 11 50 plzplz plz helpppp
OLga [1]

Answer:

i do only 1 part

hope my answer is helpful to you

5 0
2 years ago
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