Answer:
Step-by-step explanation:
Given two upward facing parabolas with equations

The two intersect at


=
x=
area enclosed by them is given by
A=![\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx](https://tex.z-dn.net/?f=%5Cint_%7B-%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D%7D%5E%7B%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D%7D%5Cleft%20%5B%20%5Cleft%20%28%20x%5E2%2B2%5Cright%20%29-%5Cleft%20%28%206x%5E2%5Cright%20%29%20%5Cright%20%5Ddx)
A=
A=
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Answer:
The last one 5x-3y=15 This is the same as y= (5/3)x -5
Step-by-step explanation:
5x-3y=15
Move 5x to the right (becoming negative)
-3y = -5x +15
Divide everything by - 3
y= (5/3)x -5
y intersect= -5 ( line crosses y coordinate at -5)
Slope = 5/3 From -5 you start counting (5 up,3 right,5 up,3 right.... OR 5 down,3 left,5 down,3 left........)
Step-by-step explanation:
9/8 × (-7/3) =
9 × -7 = -63
8 × 3 = 24
-63/24 simplify
-21/8