the Square root of 529 is 23
We have that the workdone in stretching natural length to is mathematically given as
W=9/2lbft
<h3>Workdone in stretching natural length</h3>
Question Parameters:
- A force of 128 lb is required to hold a spring stretched 2 ft <em>beyond </em>its natural length.
- Stretching it from its natural length to 9 inches beyond its natural length
Generally the Hookes equation for the Force is mathematically given as
F=Kx
Where
3.2lb=2ft*k
Thereofore
k=16
Force becomes
f=kx
f=16x
Hence
![W=8[x^2]^{3/4}_{0}](https://tex.z-dn.net/?f=W%3D8%5Bx%5E2%5D%5E%7B3%2F4%7D_%7B0%7D)
W=9/2lbft
For more information on Length visit
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Answer:100B + 50M ? 25000
Step-by-step explanation: CZ 75B has a firing pin block which makes for a longer SA trigger pull. CZ 75 has the superior trigger. Aren't the magazines different (and not interchangeable) as well? IIRC, the older 75 mags are not easy to find, and can be expensive.Apr 22, 2011
Answer:
25
Step-by-step explanation:
if four is the ratio of blue to five then divide four by 20 blue because thats the number your finding and you get 5 so then you multiply 5 by 5 and you get 25
|-5| - |7 - 4|
First, simplify |-5| to 5. / Your problem should look like: 5 - |7 - 4|
Second, simplify 7 - 4 to 3. / Your problem should look like: 5 - |3|
Third, simplify. / Your problem should look like: 2
Answer: 2
