1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anvisha [2.4K]
3 years ago
12

97) If the average of 3a and 4b is less than 50 and a is twice b, what

Mathematics
1 answer:
oee [108]3 years ago
3 0

The average of 3a and 2b satisfies

\dfrac{3a+4b}2

Then

a=2b\implies\dfrac{3(2b)+4b}2=5b

a=2b, so if a must be an integer, then the largest integer value it can take on is 19 if b can be a rational number (in which case b=9.5) or 18 if b must also be an integer.

Given that none of the provided answer choices lists 18 or 19, I'd bet there's a typo and you're supposed to find the maximum integer value of b, in which case the answer would be B as the largest integer value would be 9.

You might be interested in
Answer my math question I asked so many times I lost most of points
maks197457 [2]

Answer:

f(x) = (x+1)^2 - 9

7 0
2 years ago
Read 2 more answers
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2},

where n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19.

The mean difference \mu_1 - \mu_2 = 10.85 - 10.90 = -0.05.

The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0
4 years ago
What is the unit rate of $240 for 4 days
antiseptic1488 [7]

Answer:

$60 for 1 day

Step-by-step explanation:

60 (dollars) x 4 (days) = $240

3 0
3 years ago
Read 2 more answers
What is the value of the expression 2m + m - 4(-2m +1-m)<br> When m<br> -8?
timama [110]

Answer:

The answer should be -124.

5 0
3 years ago
What is the center of a circle circumscribed about a triangle with vertices (−2, 2) ( 2, −2)and (6, 2)? A. (2, 2) B. (2, 0) C. (
grigory [225]
C. (0,2) if you plot these points correctly on a graph, the center is at 0,2. hope this helped.
6 0
3 years ago
Other questions:
  • Can some1 turn these word sentences to numerical equations?
    9·1 answer
  • If a b and c are three different numbers which of the following equations has exactly one solution?
    14·1 answer
  • When two lines crosses, it is found that the angle opposite each other are thesame sizes. They are known as what
    11·1 answer
  • Sebastian made the following model to find the product 17 x 24 is his model correct explain
    11·2 answers
  • Find the value of a variable 104,137,154,131 x mean =130
    7·1 answer
  • PLSSSSSSSSSSSSSSSSSSSSSS HELP
    10·2 answers
  • 3x+2y=4y+6 can you put this in slope intercept form
    9·1 answer
  • Plwase help! will give brainliest! ;-;
    15·2 answers
  • What’s the x and y intercept? What’s the vertex and axis of symmetry?
    14·1 answer
  • Find the radius. Round to the nearest tenth.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!