Answer:
The maximum height of the arrow is 125 feet.
Step-by-step explanation:
The pathway of the arrow can be represented by the equation,
.....(1)
Where h is height in in feet and t is time in seconds.
It is required to find the maximum height of the arrow. For maximum height,
.
So,

Put t = 2.5 s in equation (1). So,

So, the maximum height of the arrow is 125 feet.
I'm not completely sure about this answer but here is what I got: 100•15=1500 for one day of the food booth. 50•22=1100 one day for the game booth. 1500+(x9) and 1100+(x8). (1500+x)+(1100+x)=x
Angle ADC and EDG are congruent(vertical angles)
Same side interior angles are =180
2x+4x-30=180
6x-30=180
6x=210
x=35
CDG is congruent to DGH(alternate interior)
4x-30
4(35)-30
140-30
=110
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