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Goshia [24]
3 years ago
7

Louis wants to make a scale drawing of his bathroom. The room is 12 feet long by 8 feet wide. If he uses a scale of 1cm = 4ft, h

ow big would the bedroom be in the scale drawing?
Pls helpp
Mathematics
1 answer:
Natali [406]3 years ago
4 0

Answer:

Step-by-step explanation:

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How to solve 2x-y=17;x-y=10
Nataliya [291]
The answer is that y is equal to -3 and x is equal to 7 
2x-y=17
-2(x-y)=10 )
--------------
2x-y=17
-2x+2y=-20
----------------
y=-3

x-y=10 
x-(-3)=10
x+3=10
 -3   -3
----------
x=7



8 0
3 years ago
Help me pls, math is my weak point TwT
Alja [10]

Answer:

I hope this helps

8 0
3 years ago
write an equation of the line in Slope-intercept form that has a slope of -2/3 and has a Y intercept of -4
N76 [4]

y = -2/3x - 4

simply plug into y = mx+b where m is slope and b is y intercept

7 0
3 years ago
If the diagonals of a quadrilateral bisect the angles, is the quadrilateral always a parallelogram? Explain your answer.
Liula [17]
Yes. If the diagonals bisect the angles, the quadrilateral is always a parallelogram, specifically, a rhombus.


Consider quadrilateral ABCD. If diagonal AC bisects angles A and C, then ΔACB is congruent to ΔACD (ASA). Hence AB=AD and BC=CD (CPCTC).

Likewise, if diagonal BD bisects angles B and D, triangles BDA and BDC are congruent, thus AB=BC and AD=CD. (CPCTC again). Now, we have AB=BC=CD=AD, so the figure is a rhombus, hence a parallelogram.
6 0
2 years ago
The five circles making up this archery target have diameters of length $2,4,6,8,$ and $10$. What is the total red area?
Sliva [168]

Answer:

A=15\pi\ units^2

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

It is given that the diameter of 5 circles making up the archery is 2,4,6,8, and 10.

To determine the total red area, we use the formula for area of the circle

A=\pi r^{2}

step 1

Find the Area of the 1st red circle

r=2/2=1\ unit ---> the radius is half the diameter

A_1=\pi (1)^{2}=\pi\ units^2

step 2

Find the Area of the 2nd white circle

r=4/2=2\ units ---> the radius is half the diameter

A_2=\pi (2)^{2}=4\pi\ units^2

step 3

Find the Area of the 3rd red circle

r=6/2=3\ units ---> the radius is half the diameter

A_3=\pi (3)^{2}=9\pi\ units^2

step 4

Find the Area of the 4th white circle

r=8/2=4\ units ---> the radius is half the diameter

A_4=\pi (4)^{2}=16\pi\ units^2

step 5

Find the Area of the 5th red circle

r=10/2=5\ units ---> the radius is half the diameter

A_5=\pi (5)^{2}=25\pi\ units^2

The total red area is given by

A=A_5-A_4+A_3-A_2+A_1

substitute

A=25\pi-16\pi+9\pi-4\pi+\pi

A=15\pi\ units^2

7 0
3 years ago
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