The points which represents the vertices of the given equation are; (15, −2) and (−1, −2).
<h3>Which points among the answer choices represents the vertices of the ellipse whose equation is given?</h3>
The complete question gives the equation of the ellipse as; (x-7)²/64+(y+2)²/9=1.
Since, It follows from convention that general equation of ellipse with centre as (h, k) takes the form;
(x-h)²/a² +(y-k)²/b² = 1.
Consequently, it follows from observation that the value of a and b in the given equation in the task content is; √64 = 8 and √9 = 3 respectively.
Since, 8 > 3, The vertices of the ellipse are given by; (h±a, k).
The vertices in this scenario are therefore;
(7+8, -2) and (7-8, -2).
= (15, -2) and (-1, -2).
Read more on vertices of an ellipse;
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Answer:
D
Step-by-step explanation:
Since BD and AE are parallel lines, then
∠BDC = ∠AED ( corresponding angles ), thus
4x - 5 = 97 - 2x ( add 2x to both sides )
6x - 5 = 97 ( add 5 to both sides )
6x = 102 ( divide both sides by 6 )
x = 17, hence
∠AED = 97 - 2x = 97 - (2 × 17) = 97 - 34 = 63°
∠BDE and ∠AED are same side interior angles and are supplementary, thus
10y - 3 + 63 = 180
10y + 60 = 180 ( subtract 60 from both sides )
10y = 120 ( divide both sides by 10 )
y = 12 → D
Answer:
Step-by-step explanation:
Using the formula
Initial -final/initial =%/100
89-72/89 =%/100
17/89 =%/100
Making %subject of the formula
% =17*100/89
So % =1700/89
%= 19.101
Therefore rounding off the answer we have
X=19%
