<h2>
Answer:</h2><h2>
The no of student ticket, x = 60</h2><h2>
The no of adult ticket, y =40</h2>
Step-by-step explanation:
The drama club is selling tickets to their play to raise money for the show's expenses.
Let the student ticket be represented as x and adult ticket as y
Cost of student ticket,x = $8
Cost of adult ticket,y = $12
The total number of tickets, x + y = 100 ... (1)
There was a total of $960 in revenue from the sale of 100 total tickets.
8x + 12y = 960 ...(2)
Multiplying eq(1) by 8, we get
8x + 8y = 800 ...(3)
Subtract eq (3) from (2), we get
4y = 160
y = 40, sub in eq (1)
x = 60
The no of student ticket, x = 60
The no of adult ticket, y =40
