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IceJOKER [234]
3 years ago
13

What is the value of (g*h)(-3)?

Mathematics
2 answers:
slega [8]3 years ago
8 0
ANSWER


\boxed {(g \circ \: h)( - 3) =  \frac{ 8}{ 5}}



EXPLANATION

The given functions are:


g(x) =  \frac{x + 1}{x - 2}


and

h(x) = 4 - x


Let us find

(g \circ \: h)(x)


This implies that,


(g \circ \: h)(x) = g(h(x))


(g \circ \: h)(x) = g(4 - x)


(g \circ \: h)(x) =  \frac{4 - x + 1}{4 - x  - 2}


(g \circ \: h)(x) =  \frac{5- x}{2 - x }



We now substitute x=-3


(g \circ \: h)( - 3) =  \frac{ 5 -  - 3}{ 2 -  - 3}



(g \circ \: h)( - 3) =  \frac{ 8}{ 5}


The correct answer is A

hichkok12 [17]3 years ago
7 0

Answer:

The correct answer is choice A.

Step-by-step explanation:

We have given two function.

g(x) = x+1 / x-2

h(x) = 4-x

We have to find the composition of given two functions.

(g*h)(x) = ? and then (g*h)(-3) = ?

(g*h)(x) = g(h(x)

putting the given values of given functions,we have

(g*h)(x) = g(4-x)

(g*h)(x) = 4-x+1 / 4-x-2

(g*h)(x) = 5-x / 2-x

(g*h)(-3) =5-(-3) / 2- (-3)

(g*h)(-3) =5+3 / 2+3

(g*h)(-3) = 8 / 5 Which is the answer.

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25/2

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Recall that for a parametrized differentiable curve C = (x(t), y(t)) with the parameter t varying on some interval [a, b]

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