Trick or treaters arrive to your house according to a Poisson process with a constant rate parameter of 20 per hour. Suppose you
1 answer:
Answer:
The expected value of interarrival time (in minutes) from the previous trick or treater to the next one is 3 minutes.
Step-by-step explanation:
We have a Poisson process with a constant rate parameter of 20 arrival per hour.
This type of processes are memory-less, meaning that no matter how much time has passed form the last event, the probabilities of an arrival stay the same.
The mean interarrival time can be calculated as the inverse of the mean arrival for the Poisson process.
If the Poisson process has a rate of 20 arrivals per hour, the mean interarrival time is:
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The order of operations is defined by the acronym PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction).
Therefore
6 + [(-24) ÷ 6] / 19
= 6 + [ -24/6 ] / 19 handle parentheses first
= 6 + (-4) /19
= 6 - 4/19 handle division
= 110/19
= 5 5/9
Answer:
Therefore
6 + [(-24) ÷ 6] / 19
= 6 + [ -24/6 ] / 19 handle parentheses first
= 6 + (-4) /19
= 6 - 4/19 handle division
= 110/19
= 5 5/9
Answer: