The top part equals 1 because anything to the power of zero equals one. then for the second one bring every variable with a negative exponent to the top and leave the 2 at the bottom
Answer:
D
Step-by-step explanation:
-2, 1 is not a point in the square but - 2, 2 is so the answer should be D -2,1
If my answer helped, kindly mark me as the brainliest!!
Answer:
The measure of the largest angle in the kite is 128 degrees
Step-by-step explanation:
we know that
The sum of the interior angles in any quadrilateral must be equal to 360 degrees
A kite is a quadrilateral
Let
A,B,C and D the measure of the interior angles
so

we have that

substitute

----> equation A
Remember that
one is four times larger than the other
so
----> equation B
substitute equation B in equation A

solve for D

Find the measure of angle C

therefore
The measure of the largest angle in the kite is 128 degrees
The given expression is ![\frac{\sqrt{2}}{\sqrt[3]{2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%20%20%20%20)
This can be simplified using the radical properties as below
![\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\](https://tex.z-dn.net/?f=%20%5C%5C%5C%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%20%20%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%20)
Now using exponent properties we can write
![\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}}=2^{\frac{1}{2}-\frac{1}{3}} \\\\\frac{\sqrt{2}}{\sqrt[3]{2}}=2^{\frac{3-2}{6}}=2^\frac{1}{6}\\\\= \sqrt[6]{2}\\](https://tex.z-dn.net/?f=%20%5C%5C%5C%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%3D2%5E%7B%5Cfrac%7B1%7D%7B2%7D-%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D2%5E%7B%5Cfrac%7B3-2%7D%7B6%7D%7D%3D2%5E%5Cfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%3D%20%5Csqrt%5B6%5D%7B2%7D%5C%5C%20)
Step-by-step explanation:
phukan = x
Nanwan = y
let this be a simultaneous equation.
x - y = 18.... equation i
x + y = 100.... equation ii
subtract equation i from equation ii
= 2y = 118
y = 59
substitute y = 59 in equation ii to get x
x + 59 = 100
x = 100- 59
x = 41
Nanwan = 59, Phukan = 41