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dimulka [17.4K]
3 years ago
6

Solve Only estimation​

Mathematics
2 answers:
PtichkaEL [24]3 years ago
5 0

Answer:

3a)1680

b)2620

4a)2130

b)13300

c)460

d)7540

Step-by-step explanation:

3a)1500+180

b)2800-170

4a)1800+330

b)7300+6000

c)670-210

d)8000-460

rjkz [21]3 years ago
4 0

Answer:

a) 1600

b) 2600

c) 2200

d) 13200

e) 500

Step-by-step explanation:

a) 1463 + 179

1400 + 200

1600

b) 2806 - 176

2800 - 200

2600

c) 1831 + 329

1900 + 300

2200

d) 7345 + 5893

7300 + 5900

13200

e) 665 - 213

700 - 200

500

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The answer would be 1/6

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sasho [114]

Answer: 10% -APEX

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Find the volume of the solid formed by revolving the region bounded by LaTeX: y = \sqrt{x} y = x and the lines LaTeX: y = 1 y =
Strike441 [17]

Answer:

The volume is:

\displaystyle\frac{37\pi}{10}

Step-by-step explanation:

See the sketch of the region in the attached graph.

We set the integral using washer method:

\displaystyle\int_a^b\pi r^2dx

Notice here the radius of the washer is the difference of the given curves:

x-\sqrt{x}

So the integral becomes:

\displaystyle\int_1^4\pi(x-\sqrt{x})^2dx

We solve it:

Factor \pi out and distribute the exponent (you can use FOIL):

\displaystyle\pi\int_1^4x^2-2x\sqrt{x}+x\,dx

Notice: x\sqrt{x}=x\cdot x^{1/2}=x^{3/2}

So the integral becomes:

\displaystyle\pi\int_1^4x^2-2x^{3/2}+x\,dx

Then using the basic rule to evaluate the integral:

\displaystyle\pi\left[\frac{x^3}{3}-\frac{2x^{5/2}}{5/2}+\frac{x^2}{2}\right|_1^4

Simplifying a bit:

\displaystyle\pi\left[\frac{x^3}{3}-\frac{4x^{5/2}}{5}+\frac{x^2}{2}\right|_1^4

Then plugging the limits of the integral:

\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(4)^{5/2}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]

Taking the root (rational exponents):

\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(2)^{5}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]

Then doing those arithmetic computations we get:

\displaystyle\frac{37\pi}{10}

6 0
3 years ago
Solve the expression x^2-100=0
enot [183]

Answer:

x = ± 10

Step-by-step explanation:

Given

x² - 100 = 0 ( add 100 to both sides )

x² = 100 ( take the square root of both sides )

x = ± \sqrt{100} ← note plus or minus, hence

x = ± 10

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How can logarithms be graphed with different bases?
yan [13]
You could use change of base formula
7 0
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