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Elena-2011 [213]

3 years ago

13

GUYS PLEASEEE HELP SOLVE THIS SYSTEM OF EQUATIONS METHOD SUBSTITUTION STEP BY STEP!!!!!!!!! 3(x-y)-2(x-y)^2= -2; 2x+7y= -5. HELP

PPPP!!!!!!!!

1 answer:

klio [65]3 years ago

7 0

3w + ( 8 v ) t if w = 4 v = 5 and t = 2

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What is the radius of a circle with circumference 5cm

coldgirl [10]

I believe the answer is 2.5 cm

4 0

4 years ago

Read 2 more answers

Which ordered pair is the solution to the system of equations?

denis23 [38]

X+y=-1
x-3y=11
------------- (subtract equation)
4y = -12
y = -12/4
y= -3
-------------- (substitute y)

x-3=-1
x=-1+3
x=2

Answer ----> A (2,-3)

-5x-3y=12
x-3y=-6

you want to multiply the top equation by -1 to swap the signs and make the x's positive like the bottom equation

5x+3y=-12
x-3y=-6

then you have to multiply every value in the bottom equation by 5 so you are able to subtract it from the top equation

5x+3y=-12
5x-15y=-30
---------------- (subtract)
18y=18
y=18/18
y=1
------------------ (substitute y)
x-3=-6
x=-6+3
x=-3

answer = (-3,1)

7 0

3 years ago

7. What is the slope of the line that passes through the points (14, -18) and (5, -12)?

worty [1.4K]

Answer:

slope = $-\frac{2}{3}$

Step-by-step explanation:

Use the slope formula $m = \frac{y_2-y_1}{x_2-x_1}$ to find the slope, or $m$ . The $x_1$ and $y_1$ represent the x and y values of one point, and the $x_2$ and $y_2$ represent the x and y values of another point. So, substitute the x and y values of the points (14, -18) and (5, -12) into the formula and solve:

$m = \frac{(-12)-(-18)}{(5)-(14)}\\m = \frac{-12+18}{5-14}\\m = \frac{6}{-9} \\m = -\frac{2}{3}$

Thus, the slope is $-\frac{2}{3}$ .

5 0

3 years ago

Simplify (6x^-2)^2(0.5x)^4. Please show your work.Thank you

Alex777 [14]

<span>(6/x²)² (x/2)⁴ = (36/x⁴) * (x⁴ / 16) = (36/16) = 9/4
Hope this helps ヾ(＾∇＾)
</span>

6 0

4 years ago

50 pts!!! Given: x - 6 1/3 ≤ 1 1/2. Choose the solution set.

maw [93]

Answer:

{x | x R, x ≤ 7 5/6 }

Step-by-step explanation:

we have

$x-6\frac{1}{3} \leq 1\frac{1}{2}$

Convert mixed number to an improper fraction first

$6\frac{1}{3}=\frac{6*3+1}{3}=\frac{19}{3}$

$1\frac{1}{2}=\frac{1*2+1}{2}=\frac{3}{2}$

substitute

$x-\frac{19}{3} \leq \frac{3}{2}$

Multiply by 6 both sides to remove the fractions

$6x-38 \leq 9$

Adds 38 both sides

$6x \leq 9+38$

$6x \leq 47$

Divide by 6 both sides

$x\leq \frac{47}{6}$

convert to mixed number

$\frac{47}{6}=\frac{42}{6}+\frac{5}{6}=7\frac{5}{6}$

substitute

$x\leq 7\frac{5}{6}$

therefore

{x | x R, x ≤ 7 5/6 }

4 0

4 years ago