Question

Separate 39 into two parts such that 4 times the smaller exceeds the larger number 6

Answer 1

Answer:

39 is separated into two parts 9 and 30.

Step-by-step explanation:

To find : Separate 39 into two parts such that 4 times the smaller exceeds the larger number 6 ?

Solution :

Let the smaller part is x and larger part is y.

39 is separate into two parts x and y

i.e. $x + y = 39$ ....(1)

4 times the smaller exceeds the larger number 6

i.e.  $4x - y = 6$ ....(2)

Solving (1) and (2) by adding both equations,

$x + y+4x-y= 39+6$

$5x=45$

$x=9$

Substitute the value of x in equation (1),

$9+ y = 39$

$y=30$

The smaller part is 9 and the larger part is 30.

39 is separated into two parts 9 and 30.