Initial value can mean many things, but what I believe it means in this area is the value that you start with (obviously), so in the equation (y=mx+b), the initial value is the b. It is where the line intercepts the y-axis, and that is your initial value, I believe!
I hope this was helpful and answered your inquiry! If you have any further doubts or questions, please let me know so that I can help you!
Answer:
No solutions
Step-by-step explanation:
–2(3x – 1) = –6x – 1
First distribute the left side
-6x + 2 = -6x - 1
Add 1 to both sides
-6x + 3 = -6x
Add 6x to both sides
3 = 0
This equation is not true because 3 does NOT equal 0. Therefor, this equation has no solutions.
Step-by-step explanation:
Hey, there!
Here,
Given that:
we need to find factor,
As it is in a^2-b^2 form as per its factor (a+b) (a-b), keeping same formula here,
25x^2 means (5x)^2
and 4 means 2^2
Now, it would be,
Therefore, it's factor would be (5x+2)(5x-2).
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer: 15
Step-by-step explanation:
First step is to find the slope of the line given
y = -x - 2
y = mx + c where m is the slope of the line so the slope of the line is -1
If 2 lines are perpendicular to one another, the product of the slopes is -1 so the slope of the perpendicular line is -1/-1 = 1
y = 1x + c or y = x + c
As the line passes through the coordinate (-5,10), we can substitute the x and y value of the coordinates into the equation
10 = -5 + c
c = 15
So the equation of the line is y = x + 15
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