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IRINA_888 [86]
4 years ago
13

Simplify 9x-7z+ 3y+10-2x

Mathematics
2 answers:
Genrish500 [490]4 years ago
4 0

Answer:

7x - 7z + 3y + 10

Step-by-step explanation:

Stella [2.4K]4 years ago
3 0

Answer:

7x+3y-7z+10

Step-by-step explanation:

You need to combine like terms.

First you do 9x-2x to get 7x

Then you put the rest of the problem together in alphabetical order first then regular numbers.

This would be x, y, z, and then 10

Lastly, you get 7x+3y-7z+10

Hope this helps!

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Please give me the correct answer ​
Ganezh [65]

Answer:

PQ = 5 units

QR = 8 units

Step-by-step explanation:

Given

P(-3, 3)

Q(2, 3)

R(2, -5)

To determine

The length of the segment PQ

The length of the segment QR

Determining the length of the segment PQ

From the figure, it is clear that P(-3, 3) and Q(2, 3) lies on a horizontal line. So, all we need is to count the horizontal units between them to determine the length of the segments P and Q.

so

P(-3, 3), Q(2, 3)

PQ = 2 - (-3)

PQ = 2+3

PQ = 5 units

Therefore, the length of the segment PQ = 5 units

Determining the length of the segment QR

Q(2, 3), R(2, -5)

(x₁, y₁) = (2, 3)

(x₂, y₂) = (2, -5)

The length between the segment QR is:

l=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

  =\sqrt{\left(2-2\right)^2+\left(-5-3\right)^2}

  =\sqrt{0+8^2}

  =\sqrt{8^2}

Apply radical rule: \sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

  =8

Therefore, the length between the segment QR is: 8 units

Summary:

PQ = 5 units

QR = 8 units

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