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3 years ago

15

I will give you brainlists if you answer this question right!!!!! Plsss help me I’ve been doing this for a while!!!! I’ll give y

ou 20 ptsssss!!

1 answer:

tatuchka [14]3 years ago

3 0

Answer:

Step-by-step explanation: do 2ydx18.84. That is the answer. I’m not telling you the answer to the multiplication, get the credit. Find the answer yourself for the multiplication.

You might be interested in

Given the figure below, find the values of x and z.

N76 [4]

Answer:

x=9

z=73

Step-by-step explanation:

Angle 107 and 8x+35 are vertical angles, so they are equal

107 = 8x+35

Subtract 35 from each side

107-35 = 8x+35

72 = 8x

Divide by 8

72/8 = 8x/8

9 =x

We also know that 107 and z are supplementary angles since they form a straight line. This means they add to 180 degrees

107+z = 180

Subtract 107 from each side

107-107+z=180-107

z =73

5 0

3 years ago

For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec

telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

$4sin(x^2) = 0$

$sin(x^2) = 0$

$x^2 = n\pi$ where n = 0, 1, 2,3, 4, 5,...

$x = \sqrt(n\pi)$

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

$f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0$

$xcos(x^2) = 0$

$x = 0$ or

$cos(x^2) = 0$

$x^2 = \frac{\pi}{2} + n\pi$ where n = 0, 1, 2, 3

$x = \sqrt{\pi(n+1/2)}$

Since we are restricting x between 0 and 3 we can stop at n = 2

So our critical points are at

x = 1.25, $y = f(1.25) = 4sin(1.25^2) = 4$

x = 2.17 , $y = f(2.17) = 4sin(2.17^2) = -4$

x = 2.8, $y = f(2.8) = 4sin(2.8^2) = 4$

For the inflection point, we can take the 2nd derivative and set it to 0

$f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0$

$cos(x^2) = 2x^2sin(x^2)$

$tan(x^2) = \frac{1}{2x^2}$

We can solve this numerically to get the inflection points are at

x = 0.81, $y = f(0.81) = 4sin(0.81^2) = 2.44$

x = 1.81, $y = f(1.81) = 4sin(1.81^2) = -0.54$

x = 2.52, $y = f(2.52) = 4sin(2.52^2) = 0.27$

3 0

3 years ago

PLEASE PLEASE HELP!! A Tigers maximum speed is 70 mph, how many miles can the cheetah run per minute

Drupady [299]

1.2 minutes per hours is the correct answer

6 0

3 years ago

Read 2 more answers

1. From 1992 to 2007 the average home price increased by 8% per year. In 1992 Anita Bath

Anuta_ua [19.1K]

Answer:

Anita Bath's home was worth $ 593,195.62 in 2007.

Step-by-step explanation:

Given that from 1992 to 2007 the average home price increased by 8% per year, and in 1992 Anita Bath bought a house for $ 187,000, to determine what was it worth in 2007 the following calculation must be performed:

2007 - 1992 = 15

187000 x 1.08 ^ 15 = X

187000 x 3.172 = X

593,195.62 = X

Therefore, Anita Bath's home was worth $ 593,195.62 in 2007.

5 0

3 years ago

The average (arithmetic mean) of five different positive integers is 30. What is the greatest possible value of one of these int

geniusboy [140]

Answer:

The Greatest possible value of one of the integer is 140.

Step-by-step explanation:

Given: The average (arithmetic mean) of five different positive integers is 30.

To find: What is the greatest possible value of one of these integers?

Explanation: we are given that the arithmetic mean of five positive integer

is 30.

Let the five positive integers are A,B,C,D,E

The arithmetic mean :

$\frac{A+B+C+D+E}{5}$ =30.

On multiplying both side by 5.

A+B+C+D+E =150.

The least values of A ,B,C and D can be 1 ,2,3,4.

Then : 1 +2+3+4+E =150

On simplification 10+E =150

On subtraction both side by 10 we get

E = 140 .

Therefore, the Greatest possible value of one of the integer is 140.

6 0

3 years ago