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2 years ago

Using the Laws of exponents, simplify the following problem.

1 answer:

7 0

$\frac{4 {}^{4} }{ {4}^{ - 8} ({4}^{ - 14}) } = \frac{4 {}^{4} }{ {4}^{ - 22 } }$

(4^4)/(4^-22)
4^(4-(-22))
4^26

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The least common multiple of two numbers is 20. The difference of the two numbers is 1.

nevsk [136]

The answer is 5. The two numbers are 5 and 4
5 x 4 = 20
5 - 4 = 1

6 0

3 years ago

Help with this math question please

gtnhenbr [62]

The answer is B x = -4. x= 3

You must factor the equation by find what 2 numbers can multiply to equal -12 and add to equal 1.

-3 and 4 are the two numbers. Now to put it in factor form would be:

(x - 3)(x + 4) = 0

They y also must equal zero.

Since its equals to 0, we must solve for x for the binomial.

x - 3 = 0 ; x = 3

x + 4 = 0 ; x = -4

The answer you get from solving x, is that answer

6 0

3 years ago

Find the limit. use l'hospital's rule if appropriate. if there is a more elementary method, consider using it. lim x→1 1 − x + l

AfilCa [17]

$\displaystyle\lim_{x\to1}\frac{1-x+\ln x}{1+\cos5\pi x}$

Evaluating the limand directly at $x=1$ gives an indeterminate form $\dfrac00$ . Apply L'Hospital's rule once and we get

$\displaystyle\lim_{x\to1}\frac{-1+\frac1x}{-5\pi\sin5\pi x}$

Again, plugging in $x=1$ returns $\dfrac00$ . Apply the rule once more:

$\displaystyle\lim_{x\to1}\frac{-\frac1{x^2}}{-25\pi^2\cos5\pi x}=\frac1{25\pi^2}\lim_{x\to1}\frac1{x^2\cos5\pi x}$

Now, in the denominator, when $x=1$ we get $x^2\cos5\pi x=-1$ , so the limit is $-\dfrac1{25\pi^2}$ .

3 0

3 years ago

Use the line plot below to

Alinara [238K]

1. There were 11 yards mowed. Each yard is represented by an x on the line plot.
2. The most amount of gas used on any one yard was 5/8 of a gallon. The least amount of gas used was 1/8 of a gallon. The difference is (5/8)-(1/8)= (4/8)= 1/2 gallon

7 0

2 years ago

Consider a geometric sequence with a first term of 4 and a fourth term of -2.916.

Orlov [11]

Answer:

a) Find the common ratio of this sequence.

Answer: -0.82

b) Find the sum to infinity of this sequence.

Answer: 2.2

Step-by-step explanation:

nth term in geometric series is given by $4\ th \ term = ar^n-1\\-2.196 = 4r^{4-1} \\-2.196/4 = r^{3} \\r = \sqrt[3]{0.549} \\r = 0.82$

where

a is the first term

r is the common ratio and

n is the nth term

_________________________________

given

a = 4

4th term = -2.196

let

common ratio of this sequence. be r

$4\ th \ term = ar^n-1\\-2.196 = 4r^{4-1} \\-2.196/4 = r^{3} \\r = \sqrt[3]{-0.549} \\r = -0.82$

a) Find the common ratio of this sequence.

answer: -0.82

sum of infinity of geometric sequence is given by = a/(1-r)

thus,

sum to infinity of this sequence = 4/(1-(-0.82) = 4/1.82 = 2.2

4 0

2 years ago