Answer:
-1.2
Step-by-step explanation:
<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>
<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>
<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>
<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
-8 and +8 equal 0 since they cancel out. It's basically 8-8. So that leaves you with 0-(-7). The two negatives make a positive, now you're left with 0+7=7. Your answer is 7. Hope this helps :)
Answer:
The answers is "
Option B".
Step-by-step explanation:

Where,
predicted value of lead content when traffic flow is 15.


Calculating thet-critical value
The lower predicted value 

When
of CI use as the expected lead content:

Answer:
a1=12
a6=12
a5=20
a3=20
a4=15
a2=15
as=94
Step-by-step explanation:
it is asking for each of the areas
I'm assuming As stands for areas summed