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snow_lady [41]
3 years ago
9

Vasko was renting a high performance bicycle for his Olympic training. Bicycle A is $25 per month and requires a down payment of

$500. Bicycle B is $50 per month rent and requires a down payment $200. How many months would Vasko need to rent the bikes in order for the total cost to be the same?
Mathematics
1 answer:
Agata [3.3K]3 years ago
7 0
You need an equation system.

First, translate the text into equations :

y = total price for the bike
x = number of months

first bike :
y = 25x + 500

second bike :
y = 50x + 200

Then you have to solve the system by placing the two equations side by side and comparing them.

25x + 500 = 50x + 200

Solve to find the value of x
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Simplify (4/5-2). ignore this it has to be 20 characters to work
WINSTONCH [101]

Answer:

-1.2

Step-by-step explanation:

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2 years ago
Please help ASAP !!! Thank you !
snow_tiger [21]
<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>

<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>

<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>

<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>

8 0
3 years ago
(-8)+8-(-7)<br><br> answer? please help
Dima020 [189]
-8 and +8 equal 0 since they cancel out. It's basically 8-8. So that leaves you with 0-(-7). The two negatives make a positive, now you're left with 0+7=7. Your answer is 7. Hope this helps :)
7 0
3 years ago
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Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow
prisoha [69]

Answer:

The answers is " Option B".

Step-by-step explanation:

CI=\hat{Y}\pm t_{Critical}\times S_{e}

Where,

\hat{Y}= predicted value of lead content when traffic flow is 15.

\to df=n-1=8-1=7

 95\% \ CI\  is\  (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\

     =\frac{1059.8}{2}\\\\=529.9

Calculating thet-critical valuet_{ \{\frac{\alpha}{2},\ df \}}=-2.365

The lower predicted value =529.9-2.365(Se)

463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076

When 99\% of CI use as the expected lead content: \to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)

8 0
3 years ago
I don't get it please help me and please clarify your explanations , thank you sm​
agasfer [191]

Answer:

a1=12

a6=12

a5=20

a3=20

a4=15

a2=15

as=94

Step-by-step explanation:

it is asking for each of the areas

I'm assuming As stands for areas summed

6 0
3 years ago
Read 2 more answers
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