Cone details:
Sphere details:
================
From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.
<u>Using Pythagoras Theorem</u>
(a)
TO² + TU² = OU²
(h-10)² + r² = 10² [insert values]
r² = 10² - (h-10)² [change sides]
r² = 100 - (h² -20h + 100) [expand]
r² = 100 - h² + 20h -100 [simplify]
r² = 20h - h² [shown]
r = √20h - h² ["r" in terms of "h"]
(b)
volume of cone = 1/3 * π * r² * h
===========================
To find maximum/minimum, we have to find first derivative.
(c)
<u>First derivative</u>
<u>apply chain rule</u>
<u>Equate the first derivative to zero, that is V'(x) = 0</u>
<u />
<u>maximum volume:</u> <u>when h = 40/3</u>
<u>minimum volume:</u> <u>when h = 0</u>
Since she wrote the numbers 1-100, we know that the probability for one number is 1/100.
If she selects a number without looking, it's a 1/100 chance she'll pull out one specific number.
However, here we need to find the probability of a number below 5. There are four numbers below 5 from the range to 1-100 and they are 1, 2, 3, and 4.
Therefore, since there are 4 numbers below 5, we have a 4/100 chance of Jane pulling out a number below 5.
In simplified terms it would be 
In decimal form, it would be 0.04
1, because 1 1/3 is only 1/3, or 0.3 recurring, away from 1, but it is 2/3, or 0.6 recurring, away from 2.
If the number of samples is increased, this actually leads
to a reduction in error of the distribution. This is because of the
relationship between variation and sample size which has the formula of:
σx = σ / sqrt (n)
So from the formula we can actually see that the variation
and sample size is inversely proportional.
Which means that increasing the sample size results in a
reduction of variation.
Answer:
It will have less variation
Answer:
The correct answer is 2.2.
Step-by-step explanation:
The following represents the probability distribution for the daily demand of microcomputers at a local store:
Demand Probability
f(0)= .1
f(1)= .2
f(2)= .3
f(3)= .2
f(4)= .2.
Expectation of a discrete probability function f of the random variable x is given by ∑ x × f(x).
Thus the expected value of demand is given by
0.1 × 0 + 0.2 × 1 + 0.3 × 2 + 0.2 × 3 + 0.2 × 4 = 2.2.
The expected daily demand is 2.2.
