3 years ago

C^2-4c+cd-4d=(c-4)() find the missing factor

1 answer:

6 0

It is (c+d)

you can basically use FOIL (first,outside,inside,last) to solve this.

you know the first term of the factor has to be C because of the c^2

the second then has to be D because you haven't seen D in the factor yet and it is in the equation.

then you know from the equation that the terms with D are not negative so D isn't negative so you have form the information above (c+d)

You might be interested in

Find the radius of the circle if the center is at (1, 2) and the point (-3, 4) lies on the circle.

Anton [14]

Answer:

2√5

Step-by-step explanation:

The radius is the distance from the center to a point anywhere along the edge of the circle. To find the distance between these two points, use the distance formula.

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(1--3)^2 + (2-4)^2}\\ d = \sqrt{4^2 + -2^2}\\ d = \sqrt{16 + 4}\\ d = \sqrt{20} \\d = 2\sqrt{5}$