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sweet [91]
3 years ago
10

C^2-4c+cd-4d=(c-4)() find the missing factor

Mathematics
1 answer:
Nadya [2.5K]3 years ago
6 0
It is (c+d)

you can basically use FOIL (first,outside,inside,last) to solve this.

you know the first term of the factor has to be C because of the c^2

the second then has to be D because you haven't seen D in the factor yet and it is in the equation.

then you know from the equation that the terms with D are not negative so D isn't negative so you have form the information above (c+d)
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So in this case, we have to replace the known value.
y=3
y=-2x+3

3=-2x+3

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\frac{3-3}{2}= x

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For the second one we have...
y=3x+2
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For this we substitute the y in any of the equation...
3x+2=-3x-4

We move the unknown values to one side and the ones without unlown values to the other side...
3x+3x=-4-2

Then we solve
6x=-6

Then we leave the unknown value alone.
x=\frac{-6}{6}

Then solve for x.
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Then for our y value we return to one of the original equations and substitute the x value.
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y=3(-1)+2
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