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Gnoma [55]
3 years ago
8

The graph below is based on data collected from a sixth grade class.

Mathematics
2 answers:
KiRa [710]3 years ago
8 0
<h2>Answers :</h2>

a) There are <u>5 subjects</u> in Grade six.

b) 5+7+4+4+5 = There are <u>2</u><u>5</u><u> </u><u>students</u><u> </u> in Grade six.

c) My favourite subject is <u>Maths</u>.

d) My classes start at <u>12 noon.</u>

<h2>So ,</h2>

The question can be :

<h3>What is the class schedule, number of students and subjects in Grade 6? </h3>
spin [16.1K]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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5. Write an expression equivalent to x - 3y + 4.​
Pepsi [2]

Answer:

2x - 6y + 8

Step-by-step explanation:

7 0
3 years ago
Scientific notation
tatiyna

Answer:

51,760

Step-by-step explanation:

Move the decimal place 4 tens places to the right (Positively)

51,760

I hope this helped!

7 0
3 years ago
Express in the form of p/q :<br><br> (i) 0.12▁3 (ii) 0. ▁621 (iii) 2.2▁18​
konstantin123 [22]

Answer:

1)0.123( bar on 3)

Let X = 0.123 ( bar on 3)

Then X = 0.1233 --------(1)

Multiply equation (1) by 100 we get,

100X = 12.33 --------(2)

Again multiply equation (2) by 10 we get,

1000X = 123.33 -------(3)

Subtract equation (2) from equation (3) we get,

1000X = 123.33

100X = 12.33

____________

900X = 111

X = 111/900

Hence,

0.123 ( bar on 3) is in the form of 111/900 which is in the form of P/Q.

6 0
4 years ago
Use simultaneous equations to solve the following. Three kilograms of jam and two kilograms of butter cost $29 and six kilograms
artcher [175]

Answer:

The cost of 1kg jam is $7 and the cost of 1kg butter is $4

Step-by-step explanation:

Let jam = x

butter = y

3x + 2y = 29 -----(1)

6x + 3y = 54 -----(2)

(1)×2 ->

6x + 4y = 58 -----(3)

(3)-(2) ->

y = 4

suby=4into(2)

6x + 3(4) = 54

6x = 42

x = 7

(Correct me if i am wrong)

6 0
3 years ago
FOR BRAINLIEST<br> Express 0.64 as a fraction in lowest terms.<br> 5/32<br> 64/10<br> 16/25<br> 4/5
Nadusha1986 [10]

Answer:In its decimal form, it says  ' 64 / 100 '.

In order to change it to its lowest terms, we look to see whether the

numerator and denominator have a common factor greater than ' 1 '.

If they do, then we can divide numerator and denominator by their

common factor, and have the same fraction in lower terms.

The common factors of  64  and  100  are  1,  2, and  4 .

We could divide top and bottom by 2, but that wouldn't finish the job.

It's always best to divide them by their greatest common factor, and

once you do that, you're done.

Dividing the numerator and denominator both by  4,

we get the fraction in its lowest terms:

        0.64  =  64/100  =  16/25

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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