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Gnoma [55]
3 years ago
8

The graph below is based on data collected from a sixth grade class.

Mathematics
2 answers:
KiRa [710]3 years ago
8 0
<h2>Answers :</h2>

a) There are <u>5 subjects</u> in Grade six.

b) 5+7+4+4+5 = There are <u>2</u><u>5</u><u> </u><u>students</u><u> </u> in Grade six.

c) My favourite subject is <u>Maths</u>.

d) My classes start at <u>12 noon.</u>

<h2>So ,</h2>

The question can be :

<h3>What is the class schedule, number of students and subjects in Grade 6? </h3>
spin [16.1K]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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Find the area of each shape, please help and I will give a lot points
Alex73 [517]

Answer:

15. Area of parallelogram = bh

    b = 9m

    h = 4m

    a = 9*4 = 36m^2

   You can also use the rectangle property here.

    a = l*b

    l = 9

    b = 6

    a = 9*6 = 54 m^2

    Though I would prefer the first one better.

16. Area of triangle = 1/2*bh

    b = 17m

    h = 3

    a = 17*3/2 = 51/2 = 25.5m^2

18. Area of a trapezium = a+b/2*h (a and b are two parallel sides and h the            height)

a = 15

b = 7

h = 15

a = 15+7/2*15 = 22/2*15 = 11*15 = 165m^2

19. Area of triangle = 1/2*bh

    b = 24

    h = 7

    a = 24*7/2 = 168/2 = 84

Hope u understood

Please mark as brainliest

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5 0
3 years ago
Quadrilateral MNPQ is shown.
vlabodo [156]

Answer:

62

Step-by-step explanation:

5 0
3 years ago
In a sample of 41 temperature readings taken from the freezer of a restaurant, the mean is 29.7 degrees and the population stand
yKpoI14uk [10]

Answer: =(29.1596\text{ degrees},\ 30.2404\text{ degrees})

Step-by-step explanation:

Given: Sample size: n = 41

Sample mean \overline{x}= 29.7 degrees

Population standard deviation \sigma=2.7 degrees

Confidence level (c) =  80% =0.80

Significance level (a) = 1- c = 1-0.80 = 0.20

z-score for 80% confidence level : z = 1.2816   [from z-table]

Confidence level for population mean :-

\overline{x}\pm z\dfrac{\sigma}{\sqrt{n}}

=29.7\pm ( 1.2816)\dfrac{2.7}{\sqrt{41}}

=29.7\pm ( 1.2816)\dfrac{2.7}{6.403124}

=29.7\pm ( 1.2816)(0.42167)

=29.7\pm 0.5404

=(29.7-0.5404,\ 29.7+0.5404)

=(29.1596,\ 30.2404)

Hence, 80% confidence interval for the temperatures in the freezer =(29.1596\text{ degrees},\ 30.2404\text{ degrees})

7 0
3 years ago
In rectangle KLMN, KM = 10x + 24 and LN = 64. Find the value of x.
Mice21 [21]
_________X=30____
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3 years ago
I need help with this ASAP. Thank you for the help
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Answer:

The relationship is not a function

Step-by-step explanation:

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