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2 years ago

What's another way to write (6+7)x?

Mathematics

2 answers:

Akimi4 [234]2 years ago

7 0

You can write it as 13x. I hope this helps!

6+7=13 (13)x=13x

Annette [7]2 years ago

6 0

I think 6x+7x because i think u distribute

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[ (-5) + (-4) ]x • (-5) - (-7)x + (-3)x

pantera1 [17]

Answer: 49x

Step-by-step explanation:

first, i rewrite the equation, removed the parentheses, and multiplied it all out.

(-5-4)x x (-5) + 7x - 3x

then, i calculated it.

-9x x (-5) + 7x - 3x

then, i multiplied and calculated again.

45x + 7x - 3x = 49x

3 0

3 years ago

Help on this please

eimsori [14]

Answer:

Opening: Opens upwards

Axis of Symmetry: -7/2

Vertex: (-7/2, -81/4)

X - intercepts: (1, 0) and (-8, 0)

Y - intercept: (0, -8)

Step-by-step explanation:

Opening: 'a' is greater than zero

Axis of Symmetry:

$\frac{-7}{2(1)} =\frac{-7}{2}$

Vertex:

$y= (\frac{-7}{2})^{2} +7(\frac{-7}{2}) -8\\y= (\frac{49}{4}) +(\frac{-49}{2}) -8\\y= \frac{49}{4} +\frac{-98}{4} -8\\y=\frac{-49}{4}-8\\y = \frac{-81}{4}$

X - intercepts:

(x-1)(x+8)

x = 1 and x = -8

Y - intercept: (0, -8)

$y= 0^{2} +7(0) -8\\\\y= -8\\$

5 0

2 years ago

A sports statistician was interested in the relationship between game attendance in thousands and the number of wins for basebal

pantera1 [17]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Show that the two triangles given beside are similar and calculate the lengths of sides PQ and PR.

Rina8888 [55]

9514 1404 393

Answer:

ΔABC ~ ΔPQR
PQ = 8
PR = 14

Step-by-step explanation:

Angles A and P are marked congruent; angles B and Q are marked congruent, so the triangles are similar by the AA similarity postulate. The similarity statement can be written ...

ΔABC ~ ΔPQR by AA similarity

The ratio of sides of PQR to ABC is the ratio QR/BC = 12/6 = 2. That is, each side in the larger triangle is 2 times the length of the corresponding smaller side.

PQ = 2·AB = 2·4 = 8

PR = 2·AC = 2·7 = 14

The side lengths of interest are ...

PQ = 8, PR = 14

5 0

2 years ago

Find an integer value of b that makes x^2 + bx - 81 factorable.

Kaylis [27]

Answer:

b = 80

Step-by-step explanation:

Given that,

x² + bx - 81

To find,

value of b

What is factorable?

A polynomial equation with highest degree 2 is if factorable when

we can find two terms which when multiples = -81x², <em> ( x² * - 81 = -81x² ) </em>
and when add = bx

possible factors:

-1x * 81x = -81x² (Accepted)
1x * -81x= -81x² (rejected)
9x * -9x = -81x² (rejected)
-9x * 9x = -81x² (rejected)

Only when -1x , 81x is added -1x + 81x = 80x

so, bx = 80x

b = 80

<h3>The equation is x² + 80x - 81</h3>

5 0

2 years ago