The magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T
<h3>Magnetic field inside solenoid</h3>
The magnetic field inside the central area of the solenoid is given by B = μ₀ni where
- μ₀ = permeability of free space = 4π × 10⁻⁷ Tm/A,
- n = number of turns per unit length = 3,170 turns/m and
- i = current in solenoid = 6.7 A
Since B = μ₀ni
Substituting the values of the variables into the equation, we have
B = μ₀ni
B = 4π × 10⁻⁷ Tm/A × 3,170 turns/m × 6.7 A
B = 4π × 10⁻⁷ Tm/A × 21239 A-turns/m
B = 84956π × 10⁻⁷ T
B = 266897.15 × 10⁻⁷ T
B = 0.026689715 T
B ≅ 0.0267 T
So, the magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T
Learn more about magnetic field inside a solenoid here:
brainly.com/question/25562052
Answer:
c
Step-by-step explanation:
0.1=1/10
1/10 is just the fraction form of 0.1
Answer:
x = HJ/5 + 3/5
HJ = 5x - 3 = 5 (11) - 3 = 55 - 3 = 52
JK = 8x - 9 = 8(11) - 9 = 88 - 9 = 79
Answer:
123
Step-by-step explanation:
idk
