Answer:
The cytosolic and mitochondrial pools of CoA are kept separate, and no radioactive CoA from the cytosolic pool enters the mitochondrion.
Explanation:
- Fatty acyl group condensed with CoA in the cytosol are first transferred to carnitine and in this process, CoA is released.
- After this, it is transported into the mitochondrion, where it is again condensed with CoA.
- In this way, the cytosolic and mitochondrial pools of CoA are kept separate, and due to this reason, no radioactive CoA from the cytosolic pool enters the mitochondrion.
- Therefore, according to the given question, the C14 CoA that is added into the liver homogenate along with palmitate shows cytosolic radioactive fraction but not mitochondrial as in the mitochondria a different CoA joins palmitate and not the one containing C14.
The correct answer is the last statement.
If the regulatory serine is mutated to alanine, then acetyl-CoA carboxylase will get activated spontaneously and will produce malonyl-CoA. The increased concentrations of malonyl-CoA will obstruct the oxidation of fatty acids by preventing the entry of fatty acids into the mitochondria.
It is because the AMP-activated protein kinase phosphorylates the serine residues of acetyl-CoA carboxylase to inactivate it. If a mutation occurs in such residues, then the AMPL cannot phosphorylate acetyl-CoA carboxylase and this enzyme will get activated spontaneously.
In such a situation, there will be more than sufficient production of malonyl-CoA, which will inhibit the admittance of more fatty acid getting inside the mitochondria; this will indirectly prevent the oxidation of fatty acids.
True, because somatic cells cannot undergo meiosis, only germ cells can.
Idkgdhsjjshsysdtsdtsysgdddhdhdhhd
