The greatest value is 562.71
Hello!
As you can see, C is the cost of each uniform. This would give us the equation below, if each uniform was $60.
60=40n+260/n
Let's multiply both sides by n.
60n=40n+260
Now, let's subtract 40n from both sides.
20n=260
We divide both sides by 20.
n=13
Therefore, 13 uniforms were purchased.
I hope this helps!
Answer:
34
Step-by-step explanation:
Answer:
1 hour
Step-by-step explanation:
25min=1 poster for the shop owner
25×4=100
100×8=800
800÷25=32 posters in 8hrs for the shop owner
1hr×8=8 posters for the apprentice
thus 40 in total
