All categories

2 years ago

Find the geometric mean of 8 and 17

Mathematics

1 answer:

maria [59]2 years ago

5 0

Oh gosh oh I thought had the president of the

You might be interested in

What is the correct algebraic expression to these ?!!! Quickkkk

sammy [17]

There you go. Hope it help.

6 0

2 years ago

Read 2 more answers

How may time can 14 go into 28?

Readme [11.4K]

14 goes into 28 2 times.

3 0

2 years ago

During a cold front, the temperature in Denver, Colorado, dropped from 7 degrees C to -5 degrees C. What was the change in the t

Radda [10]

Answer:

-12 c

Step-by-step explanation:

4 0

2 years ago

3. The population P in thousands of a city can be modeled by the equation

madreJ [45]

Answer:

27 years

Step-by-step explanation:

P is measured in thosands therefore, P will have a value of 120

so it would be...

120=80e^0.015t

80e^0.015t=120

e^0.015t=120/80=3/2=1.5

e^0.015t=1.5

0.015t= In(1.5)

t=In(1.5)/0.015

∴ t≈27.03 round it to 27 years

It would be greatly appreciated if you gave me the brainlest

7 0

2 years ago

NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.

slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

$\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2$

<u>Total Surface Area</u>

Area of the isosceles triangle:

$\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2$

Total surface area:

$\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)$

<u>Volume</u>

$\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)$

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

$\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2$

<u>Total Surface Area</u>

Area of a pentagon:

$\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2$

where a is the side length.

Therefore:

$\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)$

Total surface area:

$\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)$

<u>Volume</u>

$\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)$

8 0

1 year ago