All categories

3 years ago

What two numbers add to -26 and multiply to -56

Mathematics

2 answers:

Arlecino [84]3 years ago

7 0

Awnser:

-28 & 2

Step-by-step explanation:

-28 x 2 = -56

-28 + 2 = -26

sweet [91]3 years ago

3 0

Answer:

-28 and 2

Step-by-step explanation:

You might be interested in

I need to find te missing angle for this question

ki77a [65]

Answer:

the question is missing, please try again.

Step-by-step explanation:

3 0

3 years ago

Help thanks ASAP pls

lakkis [162]

Answer:

Step-by-step explanation:

There is four graphs that are given to you and you must identify which one is logical. For you I'll explain how this works. Suppose you rented a bus but you went by yourself so that means you'll have to pay the full 400. However, if you have a buddy then you'll have to pay 200 while your buddy pays the other 200.

Basically 400/x

x=the amount of people going on the trip.

The reason why it's not C since you'll notice that the 3rd dot nearest to the left is 200 which 200 times 3 doesn't equal up to 800.

7 0

3 years ago

(02.03 MC)

babunello [35]

Answer:

y = - 2x - 4

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, - 4) ← 2 points on the line

m = $\frac{-4-0}{0-(-2)}$ = $\frac{-4}{0+2}$ = $\frac{-4}{2}$ = - 2

the line crosses the y- axis at (0, - 4 ) ⇒ c = - 4

y = - 2x - 4 ← equation of line

4 0

2 years ago

Five cards are dealt from a standard 52-card deck. (a) What is the probability that we draw 1 ace, 1 two, 1 three, 1 four, and 1

labwork [276]

Answer:

Step-by-step explanation:

As there are total 52 cards in a deck and we have to draw a set of 5 cards, we can use the formula of combination to find the total number of possible ways of drawing 5 cards.

Number of ways to draw 5 cards = $N_T$

$N_T\;=\;({}^NC_k)\\\\N_T\;=\;({}^{52}C_5)\\\\N_T\;=\;2,598,960$

(a) Assuming the cards are drawn in order (would not affect the probability). The of getting Ace, 2, 3, 4 and 5 can be obtained by multiplying the probability of getting cards below 6 (20/52) with the probability of getting 5 different cards (4 choices for each card).

$P(a)\;=\;\frac{20}{52}*\frac{4}{52}*\frac{4}{51}*\frac{4}{50}*\frac{4}{49}*\frac{4}{48}\\\\P(a)\;=\; 1.3133*10^{-6}$

(b) For a straight we require our set to be in a sequence. The choices for lowest value card to produce a sequence are ace, 2, 3, 4, 5, 6, 7, 8, 9, or 10. Hence, the number of ways are $({}^{10}C_1)$ .

For each card we can draw from any of the 4 sets. It can be described mathematically as: $({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)\;=\;[({}^{4}C_1)^5]$