First, I would create a number line that includes the number -4 to 4, with 1/4 notches (3 notches between each number).
For 3, I would count 3 numbers to the right from zero.
For 2.25, I would count 2 numbers from zero, plus one additional notch to the right. Remember that each notch represents 1/4, or 0.25.
For the opposite of 4, I would count 4 to the left to -4. The opposite of 4 is -4.
For -(-1 1/2), I would remember that this number is actually 1 1/2, since a negative times a negative number is positive. I would count one number to the right of zero, plus two notches.
Answer:
option (d) 16.6 and 21.4
Step-by-step explanation:
Data provided in the question:
The mean life for a particular use before they failed = 19.0 hours
The distribution of the lives approximated a normal distribution
The standard deviation of the distribution = 1.2 hours
To find:
The values between which 95.44 percent of the batteries failed
Now,
In Normal distribution, the approximately 95% ( ≈ 95.44% of all values ) falls within 2 standard deviations of the mean
Therefore,
Upper limit = Mean + 2 × standard deviation
⇒ Upper limit = 19.0 + 2 × 1.2 = 21.4
Lower limit = Mean - 2 × standard deviation
⇒ Lower limit = 19 - 2 × 1.2 = 16.6
Hence,
the answer is option (d) 16.6 and 21.4
Answer:
y = (-2/5)x - 2
Step-by-step explanation:
One way to attack this problem is to interchange the coefficients of x and y and change the sign of one to +: 5x - 2y = -6 becomes 2x + 5y = c. Solving for the slope, m, we get 5y = -2x + c first, and then y = (-2/5)x + D.
Subbing 5 for x and -4 for y, we now have -4 = (-2/5)(5) + D.
Then -4 = -2 + D, so that D = -2.
The desired equation is thus y = (-2/5)x - 2.
Check: Does this pass through (5, -4)? Is -4 = (-2/5)(5) - 2 true? Yes.
Is the slope -2/5 the negative reciprocal of 5/2? Yes, it is.
A=p(1+i/k)^kn
A=5000(1+0.06/2)^2*10
A=9,030.56
