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Luba_88 [7]
3 years ago
13

Each one of the rectangles that make up the three dimensional figure is called a ___.

Mathematics
2 answers:
melisa1 [442]3 years ago
7 0

Answer:

face

Step-by-step explanation:

vovangra [49]3 years ago
4 0

Answer:

Cuboid

Step-by-step explanation:

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The sum of two numbers is 23. The difference of the numbers is 7.4. What are the two numbers?​
Brums [2.3K]
X+y=23
X-y=7.4

X+y=23
y=23-X

X-y=7.4
(23-y)-y=7.4
23-2y=7.4
-2y=-15.6
Y=7.8

X+y=23
X+7.8=23
X=15.2

Therefore the two numbers are 7.8 & 15.2

5 0
2 years ago
The​ cost, in​ dollars, of producing x belts is given by Upper C (x )equals 970 plus 12 x minus 0.076 x squared. The​ revenue, i
umka21 [38]

Answer:

$68.44 for each additional belt

Step-by-step explanation:

The cost and revenue functions are:

C(x) = 970+12x - 0.076x^2\\R(x) =43x^{\frac{3}{4}}

The profit function, P(x), is given by subtracting the cost function from the revenue function.

P(x) = R(x) - C(x)\\P(x)=43x^{\frac{3}{4}}+0.076x^2-12x-970\\

The derivate of the profit function gives us the rate at which profit changes:

\frac{dP(x)}{dx} =P'(x)=32.25x^{\frac{-1}{4}}+0.152x-12\\

For x = 484, the rate of change is:

P'(484)=32.25*484^{\frac{-1}{4}}+0.152*484-12\\P'(484) = \$68.44/belt

Profit is increasing by $68.44 for each additional belt

3 0
3 years ago
A robot can complete up to 8 tasks in 5/6 hour. each task takes the same amount of time.
storchak [24]

\bf \begin{array}{ccll} tasks&hours\\ \cline{1-2}&\\ 8&\frac{5}{6}\\\\ 1&h \end{array}\implies \cfrac{8}{1}=\cfrac{~~\frac{5}{6}~~}{h}\implies 8=\cfrac{~~\frac{5}{6}~~}{\frac{h}{1}}\implies 8=\cfrac{5}{6}\cdot \cfrac{1}{h} \\\\\\ 8=\cfrac{5}{6h}\implies 48h=5\implies h=\cfrac{5}{48}\\\\[-0.35em] \rule{31em}{0.25pt}


\bf \begin{array}{ccll} tasks&hours\\ \cline{1-2}&\\ 8&\frac{5}{6}\\\\ t&1 \end{array}\implies \cfrac{8}{t}=\cfrac{~~\frac{5}{6}~~}{1}\implies \cfrac{8}{t}=\cfrac{5}{6}\implies 48=5t \\\\\\ \cfrac{48}{5}=t\implies 9\frac{3}{5}=t

7 0
3 years ago
Read 2 more answers
∑from 1to infinity of n^2* e^-2n
Naily [24]
<span>∑ from 1 to infinity of n^2* e^(-2n) = (e^2 + e^4)/(e^2 - 1)^3 = 0.23768</span>
3 0
3 years ago
Write all numbers in a series the same way regardless of their size.<br><br> True<br> False
Yuliya22 [10]
True, no matter how big they are they go the same way

8 0
3 years ago
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