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2 years ago

PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! EXTRA POINTS DONT SKIP:((

Mathematics

1 answer:

shtirl [24]2 years ago

6 0

♡ The Question ♡

- Order the following numbers from least to greatest. Put the lowest number on the left. -25, 33, 59, -62

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♡ The Answer ♡

- -62, -25, 33, 59 <--- Least to Greatest

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♡ The Explanation/Step-By-Step ♡

- These numbers can be represented on a number line from negative numbers, to 0, to whole numbers! So the lowest numbers will be our negative numbers, then our greatest will be the whole numbers. The higher amount the number such as -62, the more farther away it is on the number line making this our LOWEST NUMBER. 59 is the highest positive number making this our HIGHEST NUMBER. Whole numbers are greater than negative numbers so we can safely assume -25 goes before 33, so our results should be: -62, -25, 33, 59!

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ Tips ♡

- Try to use a number line, if you need anymore help feel free to look up videos on how to do this or ask the questions on Brainly! Hope this helped!

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Can someone thoroughly explain this implicit differentiation with a trig function. No matter how many times I try to solve this,

Anton [14]

Answer:

$\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)(1+\sec^2(x-y)(8+x^2))}$

Step-by-step explanation:

So we have the equation:

$\tan(x-y)=\frac{y}{8+x^2}$

And we want to find dy/dx.

So, let's take the derivative of both sides:

$\frac{d}{dx}[\tan(x-y)]=\frac{d}{dx}[\frac{y}{8+x^2}]$

Let's do each side individually.

Left Side:

We have:

$\frac{d}{dx}[\tan(x-y)]$

We can use the chain rule, where:

$(u(v(x))'=u'(v(x))\cdot v'(x)$

Let u(x) be tan(x). Then v(x) is (x-y). Remember that d/dx(tan(x)) is sec²(x). So:

$=\sec^2(x-y)\cdot (\frac{d}{dx}[x-y])$

Differentiate x like normally. Implicitly differentiate for y. This yields:

$=\sec^2(x-y)(1-y')$

Distribute:

$=\sec^2(x-y)-y'\sec^2(x-y)$

And that is our left side.

Right Side:

We have:

$\frac{d}{dx}[\frac{y}{8+x^2}]$

We can use the quotient rule, where:

$\frac{d}{dx}[f/g]=\frac{f'g-fg'}{g^2}$

f is y. g is (8+x²). So:

$=\frac{\frac{d}{dx}[y](8+x^2)-(y)\frac{d}{dx}(8+x^2)}{(8+x^2)^2}$

Differentiate:

$=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}$

And that is our right side.

So, our entire equation is:

$\sec^2(x-y)-y'\sec^2(x-y)=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}$

To find dy/dx, we have to solve for y'. Let's multiply both sides by the denominator on the right. So:

$((8+x^2)^2)\sec^2(x-y)-y'\sec^2(x-y)=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}((8+x^2)^2)$

The right side cancels. Let's distribute the left:

$\sec^2(x-y)(8+x^2)^2-y'\sec^2(x-y)(8+x^2)^2=y'(8+x^2)-2xy$

Now, let's move all the y'-terms to one side. Add our second term from our left equation to the right. So:

$\sec^2(x-y)(8+x^2)^2=y'(8+x^2)-2xy+y'\sec^2(x-y)(8+x^2)^2$

Move -2xy to the left. So:

$\sec^2(x-y)(8+x^2)^2+2xy=y'(8+x^2)+y'\sec^2(x-y)(8+x^2)^2$

Factor out a y' from the right:

$\sec^2(x-y)(8+x^2)^2+2xy=y'((8+x^2)+\sec^2(x-y)(8+x^2)^2)$

Divide. Therefore, dy/dx is:

$\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)+\sec^2(x-y)(8+x^2)^2}$

We can factor out a (8+x²) from the denominator. So:

$\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)(1+\sec^2(x-y)(8+x^2))}$

And we're done!

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3 years ago

What is the value of x 3x 2x 55

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

3x+2x+55=180

5x+55=180

5x=180-55

5x=125

X=125/5

X=25

So the value of X is 25

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3 years ago

the results of a poll indicate that between 33% and 37% of the population of a town visit the library at least once a year. what

Vera_Pavlovna [14]

The margin of error is ±2%

<h3>What is Margin error?</h3>

A margin of error is a statistical measurement that accounts for the difference between actual and projected results in a random survey sample.

Let x be margin of error and y be the percentages of the population.

So,

y-x =33%

y +x = 37%

Solving above equations

2y= 70

y= 35%

and x= 2%

Hence, the margin of error is ±2%.

Learn more about this concept here:

brainly.com/question/11421935

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2 years ago

Which is bigger:<br> 3/8 or 0.38.<br> Can you tell me how to work it out?please!

Usimov [2.4K]

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3 years ago

Heres an easy question,<br><br> What is 50223 - 53253 * 51<br><br> Good luck! ;)

Ivahew [28]

2665680 is the answer

6 0

3 years ago

Read 2 more answers

PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! *EXTRA POINTS* DONT SKIP:((

PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! EXTRA POINTS DONT SKIP:((