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aleksley [76]
2 years ago
9

Really need help with this ​

Mathematics
1 answer:
IrinaVladis [17]2 years ago
5 0

Answer:

36.89°

Step-by-step explanation:

tan x = 15/20=3/4

x = 36.89

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3. The figure below is a composite shape that consists of a semicircle and an equilateral triangle (triangle
Ivenika [448]

Answer:

See explanation below

Step-by-step explanation:

Area = Area of triangle + Area of the semi circle

Area of triangle = 1/2bh

Area of triangle = 1/2 *(5/2)(4)

Area of triangle = 1/2(2.5)*4

Area of triangle = 2 * 2.5

Area of triangle = 5cm^2

Area of semicircle = πr²/2

r = 2.5cm

Area of semicircle =(3.14)(2.5)²/2

Area of semicircle = = 3.14 * 4.5

Area of semicircle = 9.8125cm^2

Area pf the figure = 5+9.8125

Area pf the figure = 14.8125cm^2

For the perimeter

Perimeter of the semicircle = 2πr

Perimeter of the semicircle = 2(3.14)(2.5)

Perimeter of the semicircle = 15.7cm

Perimeter of the semicircle = = 15.7 + 5 + 5

Perimeter of the semicircle = 25.7cm

8 0
3 years ago
Thomas had 12 juice boxes he gave some to his sisters he now has more rhan 5 left.Which inequality can be used to find j the num
Ivahew [28]

Answer:

J < T - 5

Step-by-step explanation:

T =  The number of juice boxes Thomas had

J =  The number of juice boxes Thomas gave to his sisters

Thomas had 12 juice boxes

T = 12

He gave some to his sisters he now has more than 5 left.

T - J > 5

-J > 5 - T

J < -5 + T

J < T - 5

5 0
3 years ago
Eight less than the product of seven x
lisabon 2012 [21]

Answer:

2x - 8

Step-by-step explanation:

Product of two and a number x

⇒ 2 multiply by x

⇒ 2x

Eight less than 2x

⇒ Take away 8 from 2x

⇒ 2x - 8

8 0
3 years ago
Read 2 more answers
A model rocket is launched straight upward. The solid fuel propellant pushes the rocket off the ground at an initial velocity of
anastassius [24]

Answer:

a) 72.25sec

b) 6.25secs

c) after 10.5secs and 2 secs

Step-by-step explanation:

Given the height reached by the rocket expressed as;

s(t)= -4t^2 + 50t - 84

At maximum height, the velocity of the rocket is zero i.e ds/dt  = 0

ds/dt = -8t + 50

0 = -8t + 50

8t = 50

t = 50/8

t = 6.25secs

Hence it will reach the maximum height after 6.25secs

To get the maximum height, you will substitute t - 6.25s into the given expression

s(t)= -4t^2 + 50t - 84

s(6.25) = -4(6.25)^2 + 50(6.25) - 84

s(6.25) = -156.25 + 312.5 - 84

s(6.25)  = 72.25feet

Hence the maximum height reached by the rocket is 72.25feet

The rocket will reach the ground when s(t) = 0

Substitute into the expression

s(t)= -4t^2 + 50t - 84

0 = -4t^2 + 50t - 84

4t^2 - 50t + 84 = 0

2t^2 - 25t + 42 = 0

2t^2 - 4t - 21t + 42 = 0

2t(t-2)-21(t-2) = 0

(2t - 21) (t - 2) = 0

2t - 21 = 0 and t - 2 = 0

2t = 21 and t = 2

t = 10.5 and 2

Hence the time the rocket will reach the ground are after 10.5secs and 2 secs

3 0
3 years ago
Add:
dezoksy [38]
   (4-3n-5n2)

+( -2+n-3n2)
____________________
    -2-2n-8n2

8 0
3 years ago
Read 2 more answers
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