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3 years ago

What is 2 3/4 + 1/3 and how did you solve it?

Mathematics

2 answers:

a_sh-v [17]3 years ago

5 0

Answer:

Step-by-step explanation:

Given 2 3/4 + 1/3

First change the mixed fraction to improper fraction .

That’s 2 2/3 becomes 8/3. Multiply the denominator 3 by the whole number 2 and then add it the numerator 3.

Now we have 8/3 + 1/3 .

We look for the lowest common multiple LCM of the denominators of the fractions.

The LCM is = 3

Now divide the denominator of each fraction by the LCM 3 and multiply the result by the numerator.

We have 8 + 1 /3 .

Everything divided by the LCM.

8 + 1 /3

9/3

3/1

MissTica3 years ago

3 0

Answer:

3.08 i turned it to a decimal

Step-by-step explanation:

2 3/4= 2.75

1/3=.33 and add them to get 3.08

in fraction form it is 3 1/12

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If M is the set of all square of integers that are less than 100 and N is the set of all positive odd numbers that are under 15,

ollegr [7]

A set is simply the group of numbers.

The set of M and N are: $M = \{1,4,9,16,25,36,49,64,81\}$ and $N= \{1,3,5,7,9,11,13\}$ .
The set of M n N is: $M\ n\ N = \{1,9\}$ .
The set of M u N is: $M\ u\ N = \{1,3,4,5,7,9,11,13,16,25,36,49,64,81\}$

(a) The set of M and N

Given that:

M = squares of integers less than 100

N = Positive odd numbers less than 15

So, we have:

$M = \{1,4,9,16,25,36,49,64,81\}$

$N= \{1,3,5,7,9,11,13\}$

(b) M n N and M u N

M n N is the set of common elements between sets M and N.

So, we have:

$M\ n\ N = \{1,9\}$

M u N is the set of all elements in sets M and N.

So, we have:

$M\ u\ N = \{1,3,4,5,7,9,11,13,16,25,36,49,64,81\}$

Read more about sets at:

brainly.com/question/2332158

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2 years ago

Write log3 6 as a logarithm of base 2.

Sever21 [200]

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Answer:

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Step-by-step explanation:

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