<h2>
Answer:</h2><h2>
The probability that Roy gives randomly an SUV = 15 / 47</h2>
Step-by-step explanation:
The total number of used cars owned by Roy = 47
[12 trucks + 20 cars + 15 SUV = 47 cars]
The total number in sample space, n (S) = 47
The probability that Roy is giving away and SUV = ?
Let A be the event that Roy is giving an SUV
Total no of SUV's , n (A) = 15
The probability of giving an SUV, P (A) = n (A) / n (S)
P (A) = 15 / 47
Answer: either 5, 5, 14
First, we know the median is 5. Thus, the middle value of the data is 5, so the set can now be read x, 5, y. Then, because the mode is 5 and the set is not trimodal, either x or y must be 5. Thus, the set could either be 5, 5, 14, or
-4, 5, 5. However, because it must contain only positive number, the answer is 5, 5, 14
Hope it helps <3
Answer:
57.93% probability that a trip will take at least 35 minutes.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a trip will take at least 35 minutes
This probability is 1 subtracted by the pvalue of Z when X = 35. So



has a pvalue of 0.4207
1 - 0.4207 = 0.5793
57.93% probability that a trip will take at least 35 minutes.
Answer:
Step-by-step explanation: