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sattari [20]
3 years ago
5

The average age at which adolescent girls reach their adult height is 16 years. Suppose you have a sample of 29 adolescent girls

who are developmentally delayed, and who have an average age at which they reached their adult height of 17.8 years and a sample variance of 77.4 years. You want to test the hypothesis that adolescent girls who are developmentally delayed have a different age at which they reached their adult height than all adolescent girls. In order to calculate the t statistic, you first need to calculate the estimated standard error. The estimated standard error is what?

Mathematics
1 answer:
kumpel [21]3 years ago
7 0

Answer:

standard error = 1.63

Step-by-step explanation:

To calculate the standard error we need to know the standard deviation (σ) and the sample size (n) (see the attached formula).

To obtain the standard deviation we use the given sample variance of 77.4 years:

σ²= variance

Therefore:

σ = √77.4 = 8.8

Now we can calcuate the estimated standard error:

standard error = σ /√n = 8.8/√29 = 1.63

The standard error gives us an estimation about how far the mean of the sample is from the mean of the entire population, and in this case is 1.63.

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3 years ago
HELP URGENT STEP FUNCTIONS!!!!!!! Used books cost $2.25 each. Which expression represents the total number of books that can be
irinina [24]

Answer:

A. \left \lfloor \frac{10}{2.25} \right \rfloor

Step-by-step explanation:

We are given,

The cost of one book = $2.25

Since, it takes $2.25 to buy 1 book.

The, for $10, we can get \frac{1}{2.25}\times 10 i.e. \frac{10}{2.25} = 4.44

Since, number of books cannot be in decimals.

So, the closest integer to 4.44 is 4.

Hence, we can buy 4 books from $10.

Now, according to the options:

A. \left \lfloor \frac{10}{2.25} \right \rfloor = \left \lfloor 4.44\right \rfloor = 4

B. \left \lceil \frac{10}{2.25} \right \rceil = \left \lceil 4.44 \right \rceil=5

C. \frac{10}{\left \lceil 2.25\right \rceil} =\frac{10}{3} =0.33

D. \frac{10}{\left \lfloor 2.25\right \rfloor} = \frac{10}{2} = 5

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3 0
3 years ago
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NNADVOKAT [17]
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3 years ago
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Which of the following theorems verifies that ABC~WXY?
Bumek [7]

Answer:

The correct answer is option <em>B. AA</em>

<em></em>

Step-by-step explanation:

Given two triangle:

\triangle ABC  and \triangle WXY.

The dimensions given in \triangle ABC are:

\angle A = 27^\circ\\\angle B = 90^\circ

We know that the sum of three angles in a triangle is equal to 180^\circ.

\angle A+\angle B+\angle C = 180^\circ\\\Rightarrow 27+90+\angle C=180^\circ\\\Rightarrow \angle C = 63^\circ

The dimensions given in \triangle WXY are:

\angle Y = 63^\circ\\\angle X = 90^\circ

We know that the sum of three angles in a triangle is equal to 180^\circ.

\angle W+\angle X+\angle Y = 180^\circ\\\Rightarrow \angle W+90+63=180^\circ\\\Rightarrow \angle W = 27^\circ

Now, if we compare the angles of the two triangles:

\angle A = \angle W = 27^\circ\\\angle B = \angle X= 90^\circ\\\angle C = \angle Y= 63^\circ

So, by AA postulate (i.e. Angle - Angle) postulate, the two triangles are similar.

\triangle ABC \sim \triangle WXY by <em>AA theorem.</em>

<em>So, correct answer is option B. AA </em>

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The value of the digit 3 in 730,500 is the value of the digit 3 in 73,050
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Answer:

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