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Gelneren [198K]
4 years ago
15

What is 3965 nearest 1000

Mathematics
2 answers:
lord [1]4 years ago
7 0

Answer:

4000, as 3965 rounded to the nearest thousands is 4000.

Luden [163]4 years ago
7 0

4,000, because you get the number next to the thousands and if it’s bigger than or the same as 5 you bring it up

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If 5 workers can build 5 cars in 5 days how many days would it take for 7 workers to build 7 cars
ale4655 [162]

Answer:

7 days

Step-by-step explanation:

It would also take 7 days

3 0
3 years ago
Can someone plz help me find the answer :)
vazorg [7]

Answer:

b

Step-by-step explanation:

because if you did the math right it would come out to that

4 0
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Section 5.2 Problem 21:
Fittoniya [83]

Answer:

y(x)=e^{-2x}[3cos(\sqrt{6}x)+\frac{2\sqrt{6}}{3}sin(\sqrt{6}x)] (See attached graph)

Step-by-step explanation:

To solve a second-order homogeneous differential equation, we need to substitute each term with the auxiliary equation am^2+bm+c=0 where the values of m are the roots:

y''+4y'+10y=0\\\\m^2+4m+10=0\\\\m^2+4m+10-6=0-6\\\\m^2+4m+4=-6\\\\(m+2)^2=-6\\\\m+2=\pm\sqrt{6}i\\\\m=-2\pm\sqrt{6}i

Since the values of m are complex conjugate roots, then the general solution is y(x)=e^{\alpha x}[C_1cos(\beta x)+C_2sin(\beta x)] where m=\alpha\pm\beta i.

Thus, the general solution for our given differential equation is y(x)=e^{-2x}[C_1cos(\sqrt{6}x)+C_2sin(\sqrt{6}x)].

To account for both initial conditions, take the derivative of y(x), thus, y'(x)=-2e^{-2x}[C_1cos(\sqrt{6}x+C_2sin(\sqrt{6}x)]+e^{-2x}[-C_1\sqrt{6}sin(\sqrt{6}x)+C_2\sqrt{6}cos(\sqrt{6}x)]

Now, we can create our system of equations given our initial conditions:

y(x)=e^{-2x}[C_1cos(\sqrt{6}x)+C_2sin(\sqrt{6}x)]\\\\y(0)=e^{-2(0)}[C_1cos(\sqrt{6}(0))+C_2sin(\sqrt{6}(0))]=3\\\\C_1=3

y'(x)=-2e^{-2x}[C_1cos(\sqrt{6}x+C_2sin(\sqrt{6}x)]+e^{-2x}[-C_1\sqrt{6}sin(\sqrt{6}x)+C_2\sqrt{6}cos(\sqrt{6}x)]\\\\y'(0)=-2e^{-2(0)}[C_1cos(\sqrt{6}(0))+C_2sin(\sqrt{6}(0))]+e^{-2(0)}[-C_1\sqrt{6}sin(\sqrt{6}(0))+C_2\sqrt{6}cos(\sqrt{6}(0))]=-2\\\\-2C_1+\sqrt{6}C_2=-2

We then solve the system of equations, which becomes easy since we already know that C_1=3:

-2C_1+\sqrt{6}C_2=-2\\\\-2(3)+\sqrt{6}C_2=-2\\\\-6+\sqrt{6}C_2=-2\\\\\sqrt{6}C_2=4\\\\C_2=\frac{4}{\sqrt{6}}\\ \\C_2=\frac{4\sqrt{6}}{6}\\ \\C_2=\frac{2\sqrt{6}}{3}

Thus, our final solution is:

y(x)=e^{-2x}[C_1cos(\sqrt{6}x)+C_2sin(\sqrt{6}x)]\\\\y(x)=e^{-2x}[3cos(\sqrt{6}x)+\frac{2\sqrt{6}}{3}sin(\sqrt{6}x)]

7 0
2 years ago
8.43 divided by 12.654
yarga [219]
  • decimal= .66192508

I checked I could do a fraction but my calculator won't allow

4 0
3 years ago
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