Let's call the younger student's age A and the older student's age B. The teacher's age will be T.
B = 2A
T = 5B
T+5 = 5(A+5)
Simplify the last equation.
T+5 = 5A+25
T = 5A+20
Now we have two equations solved for T, so we can set them equal to each other.
5B = 5A + 20
We can plug 2A in for B
5(2A) = 5A + 20
10A = 5A + 20
5A = 20
A = 4
To find T, we plug 4 in for A in T = 5A + 20
T = 5(4) + 20
T = 40
The answer is 40 years old.
Answer:
In 4 Hours
Step-by-step explanation:
1 hour: A: 30.25 B: 34.25
2 hours: A: 35.5 B: 38.5
3 Hours: A: 40.75 B: 42.75
4 Hours: A: 46 B: 46
MON=RTS which is A because they are congruent so you just do the same thing they did for the first triangle.
If y = 2, to find the value of y + 6, we need to substitute the value of y (2) into the expression y + 6. Substituting 2 for y, we get the equation 2 + 6. Since 2 + 6 = 8, that means that substituting y = 2 into the expression y + 6, we get 8.
