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ikadub [295]
3 years ago
15

Which fraction is halfway between 3/7 and 10/21

Mathematics
1 answer:
Aleks [24]3 years ago
6 0

Answer:

B) 19/42

Step-by-step explanation:

To find the fraction halfway between 3/7 and 10/21 we first find the difference between the fractions, half it, and then add it back on to the smaller one.

Because 10/21 > 3/7 we subtract in that order

\frac{10}{21} - \frac{3}{7} = \frac{10}{21} - \frac{9}{21} = \frac{1}{21}

Half of 1/21 is 1/42 and so the fraction halfway between 3/7 and 10/21 is

\frac{3}{7} + \frac{1}{42} = \frac{18}{42} + \frac{1}{42} = \frac{19}{42}

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50mph

Step-by-step explanation:

250divided by 5 is equal to 5

4 0
3 years ago
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Show that if X is a geometric random variable with parameter p, then
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Answer:

\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

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In order to find the expected value E(1/X) we need to find this sum:

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Lets consider the following series:

\sum_{k=1}^{\infty} b^{k-1}

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}   (a)

On the last step we assume that 0\leq r\leq b and \sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}, then the integral on the left part of equation (a) would be 1. And we have:

\int_{0}^b \frac{1}{1-r}dr=-ln(1-b)

And for the next step we have:

\sum_{k=1}^{\infty} \frac{b^{k-1}}{k}=\frac{1}{b}\sum_{k=1}^{\infty}\frac{b^k}{k}=-\frac{ln(1-b)}{b}

And with this we have the requiered proof.

And since b=1-p we have that:

\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}

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4 years ago
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By applying Pythagoras Theorem in this triangle.

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x=\sqrt{196-81}

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Answer:

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