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monitta
4 years ago
13

Fenton is bulding a modle

Mathematics
1 answer:
Lynna [10]4 years ago
3 0
What model is he building
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What is 10 x 2.3-5 in standard notation?
timofeeve [1]

Answer:I think it’s option d

Step-by-step explanation:

4 0
3 years ago
Let x represent the number of hours you read a book and y the total number of pages you have read,You already read 70 pages and
nadezda [96]
X=number of hours you read
y=number of pages

y=30x+70
number of pages after 3 hours:
y=30(3)+70
y=90+70
y=160

therefore, 160 pages after 3 hours
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(Brainlist)?!! Hope this helps!
7 0
3 years ago
4x + 2y = 8? what is the graph to this
atroni [7]
Y= -2x+4
The graph is linear
7 0
4 years ago
Read 2 more answers
Consider the following system of equations: 10 + y = 5x + x2 5x + y = 1 The first equation is an equation of a . The second equa
aleksley [76]

Answer: The first equation is an equation of a parabola. The second equation is an equation of a line.

Explanation:

The first equation is,

10+y=5x+x^2

In this equation the degree of y is 1 and the degree of x is 2. The degree of both variables are not same. Since the coefficients of y and higher degree of x is positive, therefore it is a graph of an upward parabola.

The second equation is,

5x+y=1

In this equation the degree of x is 1 and the degree of y is 1. The degree of both variables are same. Since both variables have same degree which is 1, therefore it is linear equation and it forms a line.

Therefore, the first equation is an equation of a parabola. The second equation is an equation of a line.

5 0
3 years ago
Read 2 more answers
please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up​
babunello [35]

Answer:

y'' =12x^2 -72=0

And solving we got:

x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}

We can find the sings of the second derivate on the following intervals:

(-\infty Concave up

x=-\sqrt{6}, y =-180 inflection point

(-\sqrt{6} Concave down

x=\sqrt{6}, y=-180 inflection point

(\sqrt{6} Concave up

Step-by-step explanation:

For this case we have the following function:

y= x^4 -36x^2

We can find the first derivate and we got:

y' = 4x^3 -72x

In order to find the concavity we can find the second derivate and we got:

y'' = 12x^2 -72

We can set up this derivate equal to 0 and we got:

y'' =12x^2 -72=0

And solving we got:

x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}

We can find the sings of the second derivate on the following intervals:

(-\infty Concave up

x=-\sqrt{6}, y =-180 inflection point

(-\sqrt{6} Concave down

x=\sqrt{6}, y=-180 inflection point

(\sqrt{6} Concave up

8 0
3 years ago
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