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Fittoniya [83]
2 years ago
8

Distant trees were located closer to the top of the artist's canvas than were the nearby flowers. the artist was clearly using t

he distance cue known as
Biology
1 answer:
-Dominant- [34]2 years ago
5 0
<span>Distant trees were located closer to the top of the artist's canvas than were the nearby flowers. The artist was clearly using the distance cue known as relative height. The distance cue, also known as depth perception, is related to a subject's varying size. </span>
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In multicellular organisms, cells working together and performing similar functions are called...
weqwewe [10]

Answer:

tissues

Explanation:

6 0
2 years ago
4. What is the mass of N2H4 gas in a 350.0 mL container at 50.0 °C, if the pressure of the gas is
vovangra [49]

Answer:

0.36g

Explanation:

Given parameters and conversion to standard unit

 To solve this problem we must assume ideality

Volume of N₂H₄  =  350mL  = 0.35dm³

Temperature of container  = 50°C  = 50 + 273  = 323K

Pressure  = 885torr;

               760torr  = 1atm

               885torr  = \frac{760}{885}   = 0.86atm

Unknown:

Mass of the compound  = ?

Solution:

The mass of the compound can be derived using the expression below;

         Mass = number of moles x molar mass

molar mass of N₂H₄ = 2(14) + 4(1)  = 32g/mol

To find the number of moles;

       PV  = nRT

          n  = \frac{PV}{RT}

P is the pressure

V is the volume

R is the gas constant = 0.082atmdm³mol⁻¹K⁻¹

T is the temperature

         n  = \frac{0.86 x 0.35}{0.082 x 323}   = 0.01mole

So,

    Mass  = 0.01 x 32  = 0.36g

5 0
2 years ago
Which of the following describes a path oxygen might follow as it cycles?
Juliette [100K]
I think it is answer B
5 0
3 years ago
If the initiating codon of a mRNA became mutated, what would the effect be on the transcript?
faltersainse [42]

Answer:

Translation will not occur.

Explanation:

The start codon is responsible for the initiation of translation in both prokaryotes and eukaryotes. AUG is the start codon in both which code for methionine in eukaryotes and formyl methionine and prokaryotes.

Therefore if the starts codon becomes mutated than the tRNA would not able to recognize the initiation codon and no methionine would be added as the first amino acid so the translation process might not start and no protein forms. Then the ribosome scans further for the next start codon to start translation.

7 0
3 years ago
PLEASE HELP ME WITH THIS QUESTION
Brut [27]

Answer:

D

Explanation:

5 0
3 years ago
Read 2 more answers
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