Answer:
No solution.
Step-by-step explanation:
![3^{\sqrt{m-4} } - 3^{\sqrt{2m + 8} }=0\\3^{\sqrt{m-4} } = 3^{\sqrt{2m + 8} }, so\\\sqrt{m-4} =\sqrt{2m + 8} \\m-4=2m+8\\2m-m=-4-8\\m=-12, but\\\sqrt{-4-8} =\sqrt{-12} , that \ is \ impossible \ for \ real\ numbers.\\So,\ no\ solution.](https://tex.z-dn.net/?f=3%5E%7B%5Csqrt%7Bm-4%7D%20%7D%20-%203%5E%7B%5Csqrt%7B2m%20%2B%208%7D%20%7D%3D0%5C%5C3%5E%7B%5Csqrt%7Bm-4%7D%20%7D%20%3D%203%5E%7B%5Csqrt%7B2m%20%2B%208%7D%20%7D%2C%20so%5C%5C%5Csqrt%7Bm-4%7D%20%3D%5Csqrt%7B2m%20%2B%208%7D%20%5C%5Cm-4%3D2m%2B8%5C%5C2m-m%3D-4-8%5C%5Cm%3D-12%2C%20but%5C%5C%5Csqrt%7B-4-8%7D%20%3D%5Csqrt%7B-12%7D%20%2C%20that%20%5C%20is%20%5C%20impossible%20%5C%20for%20%5C%20real%5C%20numbers.%5C%5CSo%2C%5C%20no%5C%20%20solution.)
There are 5 possibilities, and they are// H,H,H,H - H,H,H,T - H,H,T,T - H,T,T,T - T,T,T,T//
The discriminant is-
b^2-4ac=64-64=0
as the discriminant is 0, one solution will be -b/2a = -1/2
But still, we can't say that it has only one solution due to the nature of quadratic equations(It's tendency to have two solutions).
But we can say that both solutions are coincident.
Hence it has two solutions.
HOPE IT HELPED!!!☺
Answer:
Step-by-step explanation it’s d