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nikklg [1K]
3 years ago
9

I need help on b.Round each of the rainfall totals to the nearest tenth.

Mathematics
2 answers:
Greeley [361]3 years ago
6 0
R 1.0
I .9
SS 1.5
NYC 1.3
mihalych1998 [28]3 years ago
4 0
The tenth place is located where the '5' is in the following number: 2.54 
So, you look at the number <em>after </em>the 5 to see if you round it up or down.

Remember the basic rule of rounding - if the digit after the digit you are rounding is 5 or above, then you round the digit up by one. If the digit is 4 or below, then you leave that digit alone.

Let's look at the first one.
Rochester - 0.97 
The nine is in the tenths place, and the digit after it is greater than 5, so you round it up to 1.
Ithaca - 0.947
The digit after the nine is <em>below </em>five, so you don't round it up, leaving it at 0.9.
Saratoga Springs - 1.5
There is no digit after the 5, so you leave this one as 1.5.
New York City - 1.268
The digit after the 2 is greater than 5, so you round it up to 1.3.

I hope that I helped :)

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Write the number 0.00044 in scientific notation.
Gwar [14]
4.4 x 10^-4
Hope this helps!
6 0
3 years ago
Sally’s dance school had 60 students last year. This year there are only 48 students enrolled. By what percent did the enrollmen
Morgarella [4.7K]

Answer:

-20%

My brain is weird on how i figure it out but I divided 48 by 60 and got .80 so i just got the other whole to make it 1 so it is 20%. This is not the correct way to do this but this is how i got my answer.

8 0
3 years ago
Newborn babies: A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights
Fed [463]

Answer:

a) 615

b) 715

c) 344

Step-by-step explanation:

According to the Question,

  • Given that,  A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams

  • Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.

Z = (x - mean)/standard deviation

Now,

For x = 4171,  Z = (4171 - 3311)/860 = 1  

  • P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.

Next, multiply that by the sample size of 732.

  • Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171  

 

  • For part b, use the same method except x is now 1591.    

Z = (1581 - 3311)/860 = -2    

  • P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.

 

  • For part c, we now need to get two Z scores, one for 3311 and another for 5031.

Z1 = (3311 - 3311)/860 = 0

Z2 = (5031 - 3311)/860= 2  

P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772

  approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.

5 0
3 years ago
Bill has lost 40<br>pounds in 8<br>weeks. What is<br>his weekly rate?​
choli [55]

Answer:

5 pounds

Step-by-step explanation:

40 divided by 8 = 5

6 0
3 years ago
Read 2 more answers
The perimeter of an isosceles trapezoid is 28 in and the ratio of lengths of its bases is 5:3. Find the lengths of the sides of
Natalka [10]
The measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches

Let x = length of base and leg

The formula for perimeter of isosceles trapezoid is P = b₁ + b₂ + 2(leg)
Where: b = base

       P = b₁ + b₂ + 2(leg)
     28 = 3x + 5x + 2(x)
     28 = 8x + 2x
28/10 = 10x/10
    2.8 = x

Now, substitute the values:
       P = b₁ + b₂ + 2(leg)
     28 = 3(2.8) + 5(2.8) + 2(2.8)
     28 = 8.4 + 14 + 5.6
     28 = 28

Hence the measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches
8 0
3 years ago
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