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3 years ago

Non right angled triangle

Mathematics

1 answer:

Vlad1618 [11]3 years ago

8 0

Answer:

18.06

Step-by-step explanation:

law of cos()

b^2 = (16.5)^2 + (17.1)^2 - 2(16.5)(17.1)cos(65)

$\frac{3\sqrt{2}\sqrt{-3135\cos \left(65^{\circ \:}\right)+3137}}{10}\quad \begin{pmatrix}\mathrm{Decimal:}&18.06035\dots \end{pmatrix}$

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Please pick between a b c or d help please!!

yanalaym [24]

Answer:

A. (± $\sqrt{10}$ )

Step-by-step explanation:

To find the value of x, you have to square both sides of the equation. $\sqrt{x^{2} }$ cancels out to just $x$ , so you're left with $x=$ ± $\sqrt{10}$ .

4 0

3 years ago

In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

$\text{The weight of average pumpkin}=5\text{ kg}$

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0

4 years ago

Read 2 more answers

I don't get it please help me thru it.

OlgaM077 [116]

Answer:

what dont u get???

Step-by-step explanation:

6 0

3 years ago

Move numbers to the boxes to order them from least to greatest value. least greatest

Papessa [141]

Answer:

5, √26, √33, 18/3, 6.5.

Step-by-step explanation:

√26 = 5.099

√33 = 5.745

18/3 = 6.

7 0

3 years ago

Can I have help I am stuck on this problem It would mean the world if u helped me and tysm!! =-)

Marianna [84]

9514 1404 393

Answer:

10·2^-8 grams

Step-by-step explanation:

The each day, the initial amount for that day is multiplied by 1/2. After 8 days, the initial amount has been multiplied by (1/2)^8, where the exponent of 8 signifies that (1/2) is a factor 8 times in the product.

After n days, the quantity remaining is ...

q(n) = 10·(1/2)^n = 10·2^(-n)

after 8 days the remaining amount is ...

q(8) = 10·2^-8 . . . grams

4 0

3 years ago