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AURORKA [14]
4 years ago
10

PLEASE HELP!! (will give brainliest for best answer)

Mathematics
2 answers:
patriot [66]4 years ago
8 0

Answer:

C

Step-by-step explanation:

MariettaO [177]4 years ago
6 0

Answer:

C

Step-by-step explanation:

The square root would be 5

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Roger Hunt intends to purchase one of two car dealerships currently for sale in a certain city. Records obtained from each of th
ValentinkaMS [17]

Answer:

(a)   Dahl Motors = 8 Cars

       Farthington Auto Sales = 7 Cars

(b)   Roger will purchase from Farthington Auto Sales with higher weekly profit

Step-by-step explanation:

Dahl Motors / Week      

(1)          Car Sold             5         6        7       8         9        10         11          12

(2)          Probability         5%      9%     14%   24%    18%     14%     11%        5%

(3)             (2 x 3 )               0.25   0.54   0.98  1.92     1.62    1.40     1.21     0.60

(4)       Average sales = 0.25  + 0.54  + 0.98  + 1.92 + 1.62 +  1.40  +  1.21+0.60

                                   =   8.52‬ cars/ week

                                   =  8 cars /week

Profit/ Car =    $544

Total weekly profit =  544 x 8

                               =  $4,352

Farthington Auto Sales/ Week    

(1)           Car Sold             5         6        7       8         9        10      

(2)          Probability         8%      21%    31%   24%    10%     6%    

(3)          (2 x 3 )               0.40   1.26   2.17     1.92     0.9     0.6    

(4)       Average sales = 0.40  + 1.26  + 2.17  + 1.92 + 0.90 + 0.60  

                                   =   7.25‬ cars/ week

                                  = 7 cars/week

Profit/ Car =    $651

Total weekly profit =  651 x 7

                               =  $4,557‬

From the calculations above , Roger will purchase from Farthington Auto Sales

3 0
3 years ago
One math class has a greater number of students than the other. However,
Elden [556K]
The classes could each have proportions of 5 boys to 6 girls, but they don’t necessarily have to be exactly 5 to 6. The number could 5 to 6 for one class, but it could also be 10 to 12 for another class, since 10 to 12 is a scale factor of 5 to 6.
4 0
3 years ago
Read 2 more answers
four friends bought 10 lbs of nuts and shared them equally. How many pounds if nuts did each friend get
Marianna [84]
You need to do 10 divided by 4. Each friend would get 2.5 pounds of a nut.
5 0
4 years ago
In jaime's math class, 9 students chose soccer as their favorite sport. This amount represents 3/8 of the entire class. The equa
Daniel [21]

Answer:

24

Step-by-step explanation:

3/8=9

6/8=18

8/8 would be 6/8 plus 2/3 of nine which is six

6+18=24

7 0
3 years ago
For each part, give a relation that satisfies the condition. a. Reflexive and symmetric but not transitive b. Reflexive and tran
Vesnalui [34]

Answer:

For the set X = {a, b, c}, the following three relations satisfy the required conditions in (a), (b) and (c) respectively.

(a) R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)} is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)} is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)} is symmetric and transitive but not reflexive .

Step-by-step explanation:

Before, we go on to check these relations for the desired properties, let us define what it means for a relation to be reflexive, symmetric or transitive.

Given a relation R on a set X,

R is said to be reflexive if for every a \in X, (a,a) \in R.

R is said to be symmetric if for every (a, b) \in R, (b, a) \in R.

R is said to be transitive if (a, b) \in R and (b, c) \in R, then (a, c) \in R.

(a) Let R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)}.

Reflexive: (a, a), (b, b), (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \implies (b, a) \in R

Therefore R is symmetric.

Transitive: (a, b) \in R \ and \ (b, c) \in R but but (a,c) is not in  R.

Therefore, R is not transitive.

Therefore, R is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)}

Reflexive: (a, a), (b, b) \ and \ (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \ but \ (b, a) \not \in R

Therefore R is not symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)}

Reflexive: (a, a) \in R but (b, b) and (c, c) are not in R

R must contain all ordered pairs of the form (x, x) for all x in R to be considered reflexive.

Therefore, R is not reflexive.

Symmetric: (a, b) \in R and (b, a) \in R

Therefore R is symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is symmetric and transitive but not reflexive .

4 0
3 years ago
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