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3 years ago

How do you write an equation of a line given y-intercept -8 and slope 3/4

Mathematics

2 answers:

GenaCL600 [577]3 years ago

8 0

Hello there! :-)

If we are given the slope of the line and its y-intercept, we can fine the equation of the line in a flash.

First, the equation of the line should be written in slope-intercept form:

y=mx+b

In this equation, m is the slope, and b is the y-intercept.

We are given that the slope is 3/4, and -8 is the y-intercept.

Therefore, the equation of the line is y=3/4x-8.

Hope this helps. Use the comment section to clarify your doubts.

Answered by

~A felicitous teen who helps others with a smile

Good luck. :)

Lostsunrise [7]3 years ago

4 0

Answer:

$y = \frac{3}{4} x-8$

Step-by-step explanation:

You can us the equation y = m x + c to answer this question.

In ,

y = m x + c

m = slope

c = y - intercept

So, they have already given in the question that,

m = 3/4

c = (-8)

Therefore, you can simply put 3/4 and (-8) instead of m and c respectively like this.

y = m x + c

y = 3/4x - 8

Hope this helps you.

Let me know if you have any other questions :-)

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Read 2 more answers

Which graph represents a reflection of f(x) = 6(0.5)x across the x-axis?

yawa3891 [41]

Answer:

The graph that represents a reflection of f(x) across the x-axis is the blue line on the picture attached.

Explanation:

The function f(x) is:

$f(x)=6(0.5)^x$

Which is an exponential function with these features:

y-intercept: f(0) = 6(0.5)⁰ = 6(1) = 6

multiplicative rate of change: 0.5 (the base of the exponential term), which means that it is a decaying function (decreasing)

Horizontal asympote: y = 0 (this is the limit of f(x) when x approaches +∞.

The reflection of f(x) across the x-axis is a function g(x) such that g(x) = - f(x).

Thus, the reflection of f(x) across the x-axis is:

$g(x)=-6(0.5)^x$

The features of that function are:

Limit when x approaches - ∞: -∞ (thus the function starts in the third quadrant).

y-intercerpt: g(0) = -6 (0.5)⁰ = -6(1)= - 6.

Horizontal asympote: y = 0 (this is the limit of f(x) when x approaches +∞.

Note that the function never touches the x-axis, thus the function increases from -∞, crosses the y-axis at (0, -6) and continous growing approaching the x-axis but never touchs it. So, this is an increasing frunction, that starts at the third quadrant and ends in the fourth quadrant.

With those descriptions, you can sketch the graph, which you can see in the figure attached. There you have the function f(x) (the red increasing line) and its reflection across the x-axis (the blue increasing line).