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2 years ago

How do you write an equation of a line given y-intercept -8 and slope 3/4

Mathematics

2 answers:

GenaCL600 [577]2 years ago

8 0

Hello there! :-)

If we are given the slope of the line and its y-intercept, we can fine the equation of the line in a flash.

First, the equation of the line should be written in slope-intercept form:

y=mx+b

In this equation, m is the slope, and b is the y-intercept.

We are given that the slope is 3/4, and -8 is the y-intercept.

Therefore, the equation of the line is y=3/4x-8.

Hope this helps. Use the comment section to clarify your doubts.

Answered by

~A felicitous teen who helps others with a smile

Good luck. :)

Lostsunrise [7]2 years ago

4 0

Answer:

$y = \frac{3}{4} x-8$

Step-by-step explanation:

You can us the equation y = m x + c to answer this question.

In ,

y = m x + c

m = slope

c = y - intercept

So, they have already given in the question that,

m = 3/4

c = (-8)

Therefore, you can simply put 3/4 and (-8) instead of m and c respectively like this.

y = m x + c

y = 3/4x - 8

Hope this helps you.

Let me know if you have any other questions :-)

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<h3><u>Question 17</u></h3>

Given:

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$\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}$

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