Information commination technology :)
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Answer:
d. If X is NP - complete and Y is in NP then Y is NP - complete.
This can be inferred
Explanation:
The statement d can be inferred, rest of the statements cannot be inferred. The X is in NP complete and it reduces to Y. Y is in NP and then it is NP complete. The Y is not in NP complete as it cannot reduce to X. The statement d is inferred.
Answer:
See explaination
Explanation:
#include <iostream>
using namespace std;
void SelectionSortDescendTrace(int numbers[], int numElems) {
int maxInd;
for (int i = 0; i < numElems - 1; ++i) {
maxInd = i;
for (int j = i; j < numElems; ++j) {
if (numbers[j] > numbers[maxInd]) {
maxInd = j;
}
}
int temp = numbers[i];
numbers[i] = numbers[maxInd];
numbers[maxInd] = temp;
for (int j = 0; j < numElems; j++) {
cout << numbers[j] << " ";
}
cout << endl;
}
}
int main() {
int numbers[10];
int numElements = 0;
for (int i = 0; i < 10; i++) {
cin >> numbers[i];
if (numbers[i] == -1)
break;
++numElements;
}
SelectionSortDescendTrace(numbers, numElements);
return 0;
}