Question

Please Help Me On These Questions!!!!!! I need Help!!!!!

Answer 1

1. This is one confusing question... But here is what I did
x = 2y + 1
y = $3y^{2}$ + 2x

So plug in Y to solve for X
x = 2 ($3y^{2}$ + 2x) + 1
x = $-2y^{2}$ - $\frac{1}{3}$
Not sure if that's completely correct, but I'm positive I didn't make any mistakes...


5. You have to find the multiples of 60 so...

1 60
2 30
3 20
4 15
5 12  <---

7 = 12 - 5