Answer:
A) 5.12mm³
Step-by-step explanation:
Step 1
Find the volume of the bigger pyramid
This is a triangular based pyramid.
The formula to use is given as Volume of Pyramid =
1/3 × Area of the triangle × Height
Area of the triangle = 1/2 × 3 mm × 4mm = 6mm²
Volume of the large pyramid = 1/3 × 6mm² × 5mm
= 10mm³
We are given the length of the small pyramid as 4mm
We would be using was is known as scale factor to find the volume of the small pyramid
The scale factor k = (Height of the small pyramid)³/ (Height of the Large pyramid)³
k = 4³/5³
k = Volume of small pyramid/ Volume of large pyramid
Volume of small pyramid = X
Volume of large pyramid = 10mm³
Hence,
4³/5³ = X/10
Cross Multiply
= 4³ × 10 = 5³ × X
X = (4³ × 10)/ 5³
X = 5.12mm³
Answer:
2.4 Liters
Step-by-step explanation:
1,000
1
L1, start text, space, m, L, end text, equals, start fraction, 1, divided by, 1, comma, 000, end fraction, start text, space, L, end text
So, 2,400 mL
=2,400 mL×
1,000 mL
1 L
=
1
2,400
mL
×
1,000
mL
1 L
=
1,000
2,400 L
=2,400 L÷1,000
=2.4 L
Answer:
1) Total votes = 260
2) option (a) CANNOT be used to answer this question
================================================
Step-by-step explanation:
Part (A)
let all the votes = x
Violet received 156 votes which equal to 60% of all the votes
∴ 156 = 60% of x
60% = 60/100 = 0.6
∴156 = 0.6 x ⇒ x = 156/0.6 = 260 votes
Part (B) :
options (b), (c) and (d) can be used to answer this question because they will give the same result of part (A)
<u>While option (a) CANNOT be used to answer this question.</u>
Check the following
a. 0.6 times 156 = x ⇒ x = 93.6
b. 156 = 0.6x ⇒ x = 260
c. 156/0.6 = x ⇒ x = 260
d. 156/x = 60/100 ⇒ x = 260
Answer:
<em>slope of the tangent</em>
<em></em>
<em></em>
<em>The slope of the tangent to the interval (-1 ,1)</em>
<em>m = 4.6 ,5, 5.4</em>
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given function is f(x) = 0.2 x² + 5 x − 12
Slope of the tangent formula

Let y = f(x) = 0.2 x² + 5 x − 12 ...(i)
Differentiating equation(i) with respective to 'x' , we get

let x=-1

let x=0
m = 5
let x=1

<u><em>conclusion</em></u>:-
<em>slope of the tangent</em>
<em></em>
<em></em>
<em>The slope of the tangent to the interval (-1 ,1)</em>
<em>m = 4.6 , 5, 5.4</em>