All categories

4 years ago

Place these numbers on the number line. 1/4, 2/3, 3/4, 6/8

1 answer:

4 0

The best way to put them into a number line is to make sure that they've all got the same denominator, which in this case, will be 24, as this is the lowest common multiple of 3,4 and 8. You will then need to multiply these fractions accordingly. The first one (1/4) will need to be multiplied by 6 to get a denominator of 24, so this will then give you a result of 6/24. The second one (2/3), will need to be multiplied by 8, which will then give you a result of 16/24. The third one (3/4)will also need to be multiplied by 6, giving you 18/24. The final one (6/8) will need to be multiplied by 3, giving you 18/24. You will then need to put these in order, which will be- 1/4, 2/3, 3/4, and 6/8. The alternative method is to turn these into decimals- 1/4 is equivalent to 25%, which is equal to 0.25. 2/3 is equivalent to 66.66%, which is equivalent to 0.66. 3/4 is equivalent to 75%, which is equal to 0.75. 6/8 is also equivalent to 75%, which is equal to 0.75, you can then easily line them up this way. Hope this has been able to help you

You might be interested in

Ill give brainliest and 5 stars and thanks if answer this what is the result of substituting for y in the bottom equation

GREYUIT [131]

We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

Step-by-step explanation:

We have , the following equations:

$y = x+3$ and $y = x^{2} +2x -4$ . Let's substitute value of y in bottom equation:

⇒ $y = x^{2} +2x -4$

⇒ $x+3 = x^{2} +2x -4$

⇒ $x^{2} +x -7= 0$

Roots of quadratic equation are given by: a = 1, b= 1 , c = -7

$x = \frac{\sqrt{b^{2}-4ac} }{2a}$

⇒ $x = \frac{\sqrt{b^{2}-4ac} }{2a}$

⇒ $x = \frac{\sqrt{1^{2}-4(1)(-7)} }{2(1)}$

⇒ $x = \frac{\sqrt{29} }{2}$ which is actually x = ± $\frac{\sqrt{29} }{2}$ .

We know that $y = x+3$ ,

⇒ y = ± $\frac{\sqrt{29} }{2}$ + 3.

We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

5 0

3 years ago

What are the partial products that resault from multiplying 15×32

Eva8 [605]

Answer:

Partial products are 300, 150, 20 and 10. The value of 15×32 is 480.

Step-by-step explanation:

We need to find the partial products of 15×32.

First write each number as the sum of their place values.

$15=10+5$

$32=30+2$

Now, write 10 and 5 in first row, and 30 and 2 in first column as shown below:

10 5

30 30×10=300 30×5=150

2 2×10=20 2×5=10

Therefore partial products are 300, 150, 20 and 10.

Add these partial product to get the value of product.

$15\times 32 = 300+150+ 20+10$

$15\times 32 = 480$

The value of 15×32 is 480.

5 0

4 years ago

(x-8)*2/5=2 помогите пожалуйста

sweet-ann [11.9K]

(x-8)*2/5=2
0.4x - 3.2=2
0.2x-1.6=1
0.2x=2.6
x=2.6*5
x=13

^_^

7 0

3 years ago

Evaluate 13 + 6/y when y = 6

DIA [1.3K]

Answer: 14

Step-by-step explanation: According to PEMDAS you do division first so if y=6 then you do 6/6=1. Then add 13+1

4 0

3 years ago

Read 2 more answers

Make x the subject y = 4(3x-5)/9

attashe74 [19]

Answer:

3/4y +5/3 = x

Step-by-step explanation:

y = 4(3x-5)/9

Multiply each side by 9

9y = 4(3x-5)/9*9

9y = 4(3x-5)

Divide each side by 4

9/4 y = 4/4 (3x-5)

9/4y = 3x-5

Add 5 to each side

9/4y +5 = 3x-5+5

9/4y +5 = 3x

Divide by 3

9/4 y *1/3 +5/3 = 3x/3

3/4y +5/3 = x

8 0

3 years ago