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BabaBlast [244]
3 years ago
12

Use the digits 1-7 to create a seven-digit number that can be rounded to 6,300,000

Mathematics
1 answer:
oee [108]3 years ago
7 0
6,301,000 i think that. thats what my teachers have told me
    
You might be interested in
Find u*v, if u=13j and v=i+3j
Alexxx [7]

Answer:

u * v = 39 ⇒ 2nd answer

Step-by-step explanation:

* Lets explain how to solve the problem

- u and v are two vectors

- u * v means the scalar product of the two vectors

- The scalar product is a way of multiplying vectors

- The result of a scalar product is always a number not a vector

- Ex: If u = ai + bj ⇒ <a , b> and v = ci + dj ⇒ <c , d>  then the scalar

 product of them is ac + bd where ac + bd is a number

* Lets solve the problem

∵ Vector u = 13j ⇒ <0 , 13>

∵ Vector v = i + 3j ⇒ <1 , 3>

- Lets find the scalar product

∴ u * v = (0)(1) + (13)(3)

∴ u * v = 0 + 39

∴ u * v = 39

6 0
3 years ago
URGENT‼️‼️‼️‼️‼️ Is the open sentence 7x-5=2x+8 true when x=2? Justify your answer.
scZoUnD [109]

Answer:

No

Step-by-step explanation:

Substitute x = 2 into the equation and if both sides are equal then x = 2 is a solution.

left side = (7 × 2) - 5 = 14 - 5 = 9

right side = (2 × 2) + 8 = 4 + 8 = 12

left side ≠ right side

Hence x = 2 is not a solution of the equation


8 0
4 years ago
The sum of the roots of the quadratic equation x^2 + 1=0 is equal to
Naily [24]

Answer:

x² + 1 = 0

a = 1

b = 0

c = 1

x1.2 =  \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}

x1.2 =  \frac{ - 0 ±\sqrt{ {0}^{2} - (4.1.1) } }{2.1}

x1.2 =  \frac{0± \sqrt{0 - 4} }{2}

x1.2 =  \frac{± \sqrt{ - 4} }{2}

There is no real solution because the discriminant is negative

Note.

Formula diskriminan

√b² - 4ac.

if the diskrimanan is negatif, so the quadratic equatoin dont have solution

7 0
2 years ago
Explain the answer because im stuck
Tju [1.3M]

Answer:

The Proof is given below.

Step-by-step explanation:

Given:

\overline{HF}  bisect ∠ EHG.i.e

∴ ∠EHF ≅ ∠ GHF

\overline{EH} \cong \overline{GH}  

To Prove:

\overline{EF} \cong \overline{GF}  

Proof:

In  Δ EHF and Δ GHF

    EH ≅ GH     ………............{Given}

∠ EHF ≅ ∠ GHF     …………..{EF bisect ∠ EHG as given above}

     HF ≅ HF     ………............{Reflexive Property}

Δ EHF ≅ Δ GHF …................{ By Side-Angle-Side test}

∴ EF ≅ GF........{corresponding parts of congruent triangles (c.p.c.t).}

\overline{EF} \cong \overline{GF}  ....... PROVED

6 0
4 years ago
A credit card company uses these rules to calculate the minimum amount owed: For a bill of less than $100, the entire amount is
Tasya [4]

Answer:

usgs.sgmtwkgsmy

Step-by-step explanation:

tekyekyemdgmsgngemegmeey

7 0
3 years ago
Read 2 more answers
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