Question

The sum of the roots of the quadratic equation x^2 + 1=0 is equal to

Answer 1

Answer:

x² + 1 = 0

a = 1

b = 0

c = 1

$x1.2 = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$

$x1.2 = \frac{ - 0 ±\sqrt{ {0}^{2} - (4.1.1) } }{2.1}$

$x1.2 = \frac{0± \sqrt{0 - 4} }{2}$

$x1.2 = \frac{± \sqrt{ - 4} }{2}$

There is no real solution because the discriminant is negative

Note.

Formula diskriminan

√b² - 4ac.

if the diskrimanan is negatif, so the quadratic equatoin dont have solution